Calculate volume and surface area of Torus
This article is about the surface and mathematical concept of a torus.
A 3D shape made by revolving a small circle (radius r) along a line made by a bigger circle (radius R).
Torus
Property:
- It can be made by revolving a small circle (radius r) along a line made by a bigger circle (radius R).
- It is not a polyhedron
- It has no vertices or edges
- Surface Area
The surface area of a Torus is given by the formula –Surface Area = 4 × Pi^2 × R × r
Where r is the radius of the small circle and R is the radius of bigger circle and Pi is constant Pi=3.14159.
- Volume
The volume of a cone is given by the formula –Volume = 2 × Pi^2 × R × r^2
Where r is the radius of the small circle and R is the radius of bigger circle and Pi is constant Pi=3.14159.
Examples:
Input : r=3, R=7
Output :
Volume: 1243.568195
Surface: 829.045464
C++
// C++ program to calculate volume // and surface area of Torus #include<bits/stdc++.h> using namespace std; int main() { // radus of inner circle double r = 3; // distance from origin to center of inner circle // radius of black circle in figure double R = 7; // Value of Pi float pi = (float)3.14159; double Volume = 0; Volume = 2 * pi * pi * R * r * r; cout<<"Volume: "<<Volume<<endl; double Surface = 4 * pi * pi * R * r; cout<<"Surface: "<<Surface<<endl; } |
C
// C program to calculate volume // and surface area of Torus #include <stdio.h> int main() { // radus of inner circle double r = 3; // distance from origin to center of inner circle // radius of black circle in figure double R = 7; // Value of Pi float pi = (float)3.14159; double Volume = 0; Volume = 2 * pi * pi * R * r * r; printf("Volume: %f", Volume); double Surface = 4 * pi * pi * R * r; printf("\nSurface: %f", Surface); } |
Java
// Java program to calculate volume // and surface area of Torus class Test { public static void main(String args[]) { // radius of inner circle double r = 3; // distance from origin to center of inner circle // radius of black circle in figure double R = 7; // Value of Pi float pi = (float)3.14159; double Volume = 0; Volume = 2 * pi * pi * R * r * r; System.out.printf("Volume: %f", Volume); double Surface = 4 * pi * pi * R * r; System.out.printf("\nSurface: %f", Surface); } } |
Python3
# Python3 program to calculate volume # and surface area of Torus # radus of inner circle r = 3 # distance from origin to center of inner circle # radius of black circle in figure R = 7 # Value of Pi pi = 3.14159Volume = (float)(2 * pi * pi * R * r * r); print("Volume: ", Volume); Surface = (float)(4 * pi * pi * R * r); print("Surface: ", Surface); |
C#
// C# program to calculate volume // and surface area of Torus using System; class GFG { // Driver Code public static void Main() { // radius of inner circle double r = 3; // distance from origin to center // of inner circle radius of black // circle in figure double R = 7; // Value of Pi float pi = (float)3.14159; double Volume = 0; Volume = 2 * pi * pi * R * r * r; Console.WriteLine("Volume: {0}", Volume); double Surface = 4 * pi * pi * R * r; Console.WriteLine("Surface: {0}", Surface); } } // This code is contributed by Soumik |
PHP
<?php // PHP program to calculate volume // and surface area of Torus // radus of inner circle $r = 3; // distance from origin to center // of inner circle radius of black // circle in figure $R = 7; // Value of Pi $pi = (float)3.14159; $Volume = 0; $Volume = 2 * $pi * $pi * $R * $r * $r; echo "Volume: ", $Volume, "\n"; $Surface = 4 * $pi * $pi * $R * $r; echo "Surface: ", $Surface, "\n"; // This code is contributed by ajit ?> |
Output:
Volume: 1243.568195 Surface: 829.045464
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