Problem – Write a program in 8086 microprocessor to find out the addition of two 8-bit BCD numbers, where numbers are stored from starting memory address 2000 : 500 and store the result into memory address 2000 : 600 and carry at 2000 : 601.
Example –
Algorithm –
- Load data from offset 500 to register AL (first number)
- Load data from offset 501 to register BL (second number)
- Add these two numbers (contents of register AL and register BL)
- Apply DAA instruction (decimal adjust)
- Store the result (content of register AL) to offset 600
- Set register AL to 00
- Add contents of register AL to itself with carry
- Store the result (content of register AL) to offset 601
- Stop
Program –
| MEMORY ADDRESS |
MNEMONICS |
COMMENT |
| 400 |
MOV AL, [500] |
AL<-[500] |
| 404 |
MOV BL, [501] |
BL<-[501] |
| 408 |
ADD AL, BL |
AL<-AL+BL |
| 40A |
DAA |
DECIMAL ADJUST AL |
| 40B |
MOV [600], AL |
AL->[600] |
| 40F |
MOV AL, 00 |
AL<-00 |
| 411 |
ADC AL, AL |
AL<-AL+AL+cy(prev) |
| 413 |
MOV [601], AL |
AL->[601] |
| 417 |
HLT |
END |
Explanation –
- MOV AL, [500]: load data from offset 500 to register AL
- MOV BL, [501]: load data from offset 501 to register BL
- ADD AL, BL: ADD contents of registers AL AND BL
- DAA: decimal adjust AL
- MOV [600], AL: store data from register AL to offset 600
- MOV AL, 00: set value of register AL to 00
- ADC AL, AL: add contents of register AL to AL with carry
- MOV [601], AL: store data from register AL to offset 601
- HLT: stop
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Last Updated :
22 May, 2018
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