8086 program to convert 8 bit ASCII to BCD number
Last Updated :
08 Feb, 2024
Problem – Write a program to convert ASCII to BCD 8-bit number where the starting address is 2000 and the number is stored at 2050 memory address and store result in 3050 memory address.
Example-
Input : location: 2050
Data : 37
Output : location: 3050
Data : 07
Algorithm –
- Move value at [2050] into AL
- Perform AND operation on AL with 0F
- Move the content of accumulator AL into 3050
- Stop
Program –
Memory |
Mnemonics |
Operands |
Comment |
2000 |
MOV |
AL, [2050] |
[AL] <- [2050] |
2004 |
AND |
AL, 0F |
[AL] <- ([ AL] AND 0F ) |
2006 |
MOV |
[3050], AL |
[3050] <- [AL] |
200A |
HLT |
|
Stop |
Explanation – Registers AL is used for general purpose
- MOV is used to transfer the data
- AND is used for multiplication (logically)
- HLT is used to halt the program
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