Using Set() in Python Pangram Checking
Given a string check if it is Pangram or not. A pangram is a sentence containing every letter in the English Alphabet. Lowercase and Uppercase are considered the same.
Examples:
Input : str = 'The quick brown fox jumps over
the lazy dog'
Output : Yes
// Contains all the characters from ‘a’ to ‘z’
Input : str='The quick brown fox jumps over the dog'
Output : No
// Doesn’t contains all the characters from ‘a’
// to ‘z’, as ‘l’, ‘z’, ‘y’ are missing
This problem has existing solution please refer Pangram Checking link. We will solve this in Python using Set() data structure and List() comprehension. Approach is very simple,
- Convert complete sentence in lower case using lower() method of string data type in python.
- Now pass this sentence into Set(str) so that we could have list of all unique characters present in given string.
- Now separate out list of all alphabets (a-z), if length of list is 26 that means all characters are present and sentence is Pangram otherwise not.
# function to check pangram def pangram(input): # convert input string into lower case input = input.lower() # convert input string into Set() so that we will # list of all unique characters present in sentence input = set(input) # separate out all alphabets # ord(ch) returns ascii value of character alpha = [ ch for ch in input if ord(ch) in range(ord('a'), ord('z')+1)] if len(alpha) == 26: return 'true' else: return 'false' # Driver program if __name__ == "__main__": input = 'The quick brown fox jumps over the lazy dog' print (pangram(input)) |
Output:
true
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