There are 6 persons seating on a round table in which two individual have the same names. What is the probability that the two same-named individuals will be neighbors?
Answer: Total no of ways in which 6 persons can sit on a round table is (6-1)! = 5! = 120.
If we consider two same-named individuals as one person there are 5 persons who can sit in (5-1)! ways and these individuals can be seated together in 2! ways.
So, required probability =(2*(5-1)!)/(6-1)!= 2/5.
So, the answer is 2/5 = 0.4.
- Puzzle | (Round table coin game)
- Seating arrangement of n boys and girls alternatively around a round table
- Seating arrangement of N boys sitting around a round table such that two particular boys sit together
- Puzzle | 3 cuts to cut round cake into 8 equal pieces
- LCM of factorial and its neighbors
- Fill array with 1's using minimum iterations of filling neighbors
- Puzzle 51| Cheryl’s Birthday Puzzle and Solution
- Puzzle 81 | 100 people in a circle with gun puzzle
- Puzzle | 3 Priests and 3 devils Puzzle
- Puzzle 85 | Chain Link Puzzle
- Puzzle 34 | (Prisoner and Policeman Puzzle)
- Puzzle 15 | (Camel and Banana Puzzle)
- Round the given number to nearest multiple of 10
- Round the given number to nearest multiple of 10 | Set-2
- Find the number of cells in the table contains X
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.