# Number of elements that can be seen from right side

• Difficulty Level : Easy
• Last Updated : 26 Mar, 2021

Given an array of integers, consider the elements as the height of the building, find the number of buildings that can be seen from the right side.
Examples:

```Input : height[] = {2, 6, 2, 4, 0, 1}
Output : 3
we can see only 3 building i.e with height 1, 4 and 6.

Input : height[] = {4, 8, 2, 0, 0, 5}
Output : 2```

Attention reader! All those who say programming isn't for kids, just haven't met the right mentors yet. Join the  Demo Class for First Step to Coding Coursespecifically designed for students of class 8 to 12.

The students will get to learn more about the world of programming in these free classes which will definitely help them in making a wise career choice in the future.

This problem seems to be finding longest increasing sub sequence from right but actually it is not.We have to just increase the count if we encounter any building with greater height found so far.
Below is the implementation of above approach.

## C++

 `// CPP program to find number of elements``// that can be seen from right side.``#include ``using` `namespace` `std;` `int` `numberOfElements(``int` `height[], ``int` `n)``{``    ``int` `max_so_far = 0;``    ``int` `coun = 0;` `    ``for` `(``int` `i = n - 1; i >= 0; i--) {``        ``if` `(height[i] > max_so_far) {``            ``max_so_far = height[i];``            ``coun++;``        ``}``    ``}``    ``return` `coun;``}` `// Driver code``int` `main()``{``    ``int` `n = 6;``    ``int` `height[] = { 4, 8, 2, 0, 0, 5 };``    ``cout << numberOfElements(height, n);``    ``return` `0;``}`

## Java

 `// Java program to find number of elements``// that can be seen from right side.``import` `java.util.*;``class` `Solution``{`` ` `static` `int` `numberOfElements(``int` `height[], ``int` `n)``{``    ``int` `max_so_far = ``0``;``    ``int` `coun = ``0``;`` ` `    ``for` `(``int` `i = n - ``1``; i >= ``0``; i--) {``        ``if` `(height[i] > max_so_far) {``            ``max_so_far = height[i];``            ``coun++;``        ``}``    ``}``    ``return` `coun;``}` `// Driver code``public` `static` `void` `main(String args[])``{``    ``int` `n = ``6``;``    ``int` `height[] = { ``4``, ``8``, ``2``, ``0``, ``0``, ``5` `};``    ``System.out.println( numberOfElements(height, n));``  ` `}` `}``//contributed by Arnab Kundu`

## Python3

 `# Python3 program to find``# number of elements``# that can be seen from right side` `def` `numberOfElements(height, n):``    ` `    ``max_so_far ``=` `0``    ``coun ``=` `0``    ` `    ``for` `i ``in` `range``(n``-``1``,``-``1``,``-``1``):``        ``if` `height[i] > max_so_far:``            ``max_so_far ``=` `height[i]``            ``coun ``=` `coun ``+` `1``    ``return` `coun` `#Driver code``if` `__name__``=``=``'__main__'``:``    ``n ``=` `6``    ``height ``=` `[``4``, ``8``, ``2``, ``0``, ``0``, ``5``]``    ``print``(numberOfElements(height, n))``    ` `# This code is contributed by``# Shashank_Sharma    `

## C#

 `// C# program to find number of elements``// that can be seen from right side.``using` `System;` `class` `GFG``{``public` `static` `int` `numberOfElements(``int` `[]height,``                                   ``int` `n)``{``    ``int` `max_so_far = 0;``    ``int` `coun = 0;` `    ``for` `(``int` `i = n - 1; i >= 0; i--)``    ``{``        ``if` `(height[i] > max_so_far)``        ``{``            ``max_so_far = height[i];``            ``coun++;``        ``}``    ``}``    ``return` `coun;``}` `// Driver code``public` `static` `void` `Main()``{``    ``int` `n = 6;``    ``int` `[]height = { 4, 8, 2, 0, 0, 5 };``    ``Console.WriteLine(numberOfElements(height, n));``}``}` `// This code is contributed by Soumik`

## PHP

 `= 0; ``\$i``--)``    ``{``        ``if` `(``\$height``[``\$i``] > ``\$max_so_far``)``        ``{``            ``\$max_so_far` `= ``\$height``[``\$i``];``            ``\$coun``++;``        ``}``    ``}``    ``return` `\$coun``;``}` `// Driver code``\$n` `= 6;``\$height` `= ``array``(4, 8, 2, 0, 0, 5 );``echo` `numberOfElements(``\$height``, ``\$n``);` `// This code is contributed``// by Akanksha Rai`

## Javascript

 ``
Output:
`2`

My Personal Notes arrow_drop_up