Area of a Square | Using Side, Diagonal and Perimeter

Given one of the Sides S, Diagonal D, or Perimeter P of the square, the task is to find the area of the square with the given value.

Examples:

Input: S = 5 
Output: Area of the square using side = 25

Input: D = 4 
Output: Area of the square using diagonal = 8 

Input: P = 32 
Output: Area of the square using perimeter = 64 

Finding Area of Square using its Side

The area of the square of the side S is given by:

Area = Side * Side

Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;

// Function to find the area of a square
int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;

    return area;
}

// Driver Code
int main()
{

    // Given Side of square
    int S = 5;

    // Function call
    cout << areaOfSquare(S);
    return 0;
}

Java

// Java program for the above approach
class GFG{

// Function to find the area of a square
static int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;

    return area;
}

// Driver Code
public static void main(String[] args)
{

    // Given Side of square
    int S = 5;

    // Function call
    System.out.println(areaOfSquare(S));
}
}

// This code is contributed by rock_cool

Python3

# Python3 program for the above approach

# Function to find the area of a square
def areaOfSquare(S):

    # Use above formula
    area = S * S

    return area

# Driver Code
if __name__ == '__main__':

    # Given Side of square
    S = 5

    # Function call
    print(areaOfSquare(S))

# This code is contributed by Mohit Kumar

C#

// C# program for the above approach
using System;
class GFG{

// Function to find the area of a square
static int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;

    return area;
}

// Driver Code
public static void Main(string[] args)
{

    // Given Side of square
    int S = 5;

    // Function call
    Console.Write(areaOfSquare(S));
}
}

// This code is contributed by Ritik Bansal

Javascript

<script>

    // Javascript program for the above approach

    // Function to find the area of a square
    function areaOfSquare(S)
    {
        // Use above formula
        let area = S * S;

        return area;
    }

    // Given Side of square
    let S = 5;

    // Function call
    document.write(areaOfSquare(S));

    // This code is contributed by divyeshrabadiya07.

</script>

Output:

25

Time Complexity: O(1)
Auxiliary Space: O(1)

Finding Area of Square using its Diagonal

• The Area of the square of given side S is given by: 
  

Area = S * S      …(1)

• The relation between Side S and Diagonal D is given by:

   …(2) 

• Substituting the value of S from Equation (2) in Equation (1), we have:
  

Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;

// Function to find the area of a square
int areaOfSquare(int D)
{
    // Use above formula
    int area = (D * D) / 2;

    return area;
}

// Driver Code
int main()
{

    // Given diagonal of square
    int D = 4;

    // Function call
    cout << areaOfSquare(D);
    return 0;
}

Java

// Java program for the above approach
import java.util.*;

class GFG{

// Function to find the area of a square
static int areaOfSquare(int D)
{

    // Use above formula
    int area = (D * D) / 2;

    return area;
}

// Driver Code
public static void main(String[] args)
{

    // Given diagonal of square
    int D = 4;

    // Function call
    System.out.print(areaOfSquare(D));
}
}

// This code is contributed by PrinciRaj1992

Python3

# Python3 program for the above approach

# Function to find the area of a square
def areaOfSquare(D):

    # Use above formula
    area = (D * D) // 2;

    return area;

# Driver Code
if __name__ == '__main__':

    # Given diagonal of square
    D = 4;
    # Function call
    print(areaOfSquare(D));

# This code is contributed by PrinciRaj1992

C#

// C# program for the above approach
using System;

class GFG{

// Function to find the area of a square
static int areaOfSquare(int D)
{

    // Use above formula
    int area = (D * D) / 2;

    return area;
}

// Driver Code
public static void Main(String[] args)
{

    // Given diagonal of square
    int D = 4;

    // Function call
    Console.Write(areaOfSquare(D));
}
}

// This code is contributed by amal kumar choubey

Javascript

<script>
    // Javascript program for the above approach

    // Function to find the area of a square
    function areaOfSquare(D)
    {
        // Use above formula
           let area = parseInt((D * D) / 2, 10);

        return area;
    }

    // Given diagonal of square
    let D = 4;

    // Function call
    document.write(areaOfSquare(D));

</script>

Output:

8

Time Complexity: O(1)
Auxiliary Space: O(1)

Finding Area of Square using its Perimeter

• The Area of the square of given side S is given by:

Area = S * S      …(1)

• The relation between Side S and Perimeter P is given by:

P =4*S      …(2)

• Substituting the value of S from Equation (2) in Equation (1), we have:

Below is the implementation of the above formula:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;

// Function to find the area of a square
int areaOfSquare(int P)
{
    // Use above formula
    int area = (P * P) / 16;

    return area;
}

// Driver Code
int main()
{
    // Given perimeter of square
    int P = 32;

    // Function call
    cout << areaOfSquare(P);
    return 0;
}

Java

// Java program for the above approach
class GFG{

// Function to find the area of a square
static int areaOfSquare(int P)
{

    // Use above formula
    int area = (P * P) / 16;

    return area;
}

// Driver Code
public static void main(String[] args)
{

    // Given perimeter of square
    int P = 32;

    // Function call
    System.out.print(areaOfSquare(P));
}
}

// This code is contributed by amal kumar choubey

Python3

# Python3 program for the above approach

# Function to find the area of a square
def areaOfSquare(P):

    # Use above formula
    area = (P * P) // 16;

    return area;

# Driver Code
if __name__ == '__main__':

    # Given perimeter of square
    P = 32;

    # Function call
    print(areaOfSquare(P));

# This code is contributed by gauravrajput1

C#

// C# program for the above approach
using System;

class GFG{

// Function to find the area of a square
static int areaOfSquare(int P)
{

    // Use above formula
    int area = (P * P) / 16;

    return area;
}

// Driver Code
public static void Main(String[] args)
{

    // Given perimeter of square
    int P = 32;

    // Function call
    Console.Write(areaOfSquare(P));
}
}

// This code is contributed by amal kumar choubey

Javascript

<script>

// javascript program for the above approach
// Function to find the area of a square
function areaOfSquare(P)
{

    // Use above formula
    var area = (P * P) / 16;

    return area;
}

// Driver Code
//Given perimeter of square
var P = 32;

// Function call
document.write(areaOfSquare(P));

// This code is contributed by Princi Singh
</script>

Output:

64

Time Complexity: O(1)
Auxiliary Space: O(1)