Given two numbers m and n. Find the GCD of the their factorial.
Input : n = 3, m = 4 Output : 6 Explanation: Factorial of n = 1 * 2 * 3 = 6 Factorial of m = 1 * 2 * 3 * 4 = 24 GCD(6, 24) = 6. Input : n = 9, m = 5 Output : 20 Explanation: Factorial of n = 1 * 2 * 3 *4 * 5 * 6 * 7 * 8 * 9 = 362880 Factorial of m = 1 * 2 * 3 * 4 * 5 = 120 GCD(362880, 120) = 120
An efficient solution is based on the fact that GCD of two factorials is equal to smaller factorial (note that factorials have all terms common).
Below is the implementation of above approach.
- Numbers whose factorials end with n zeros
- Count natural numbers whose factorials are divisible by x but not y
- Product of first N factorials
- Find last two digits of sum of N factorials
- Find sum of factorials in an array
- Calculating Factorials using Stirling Approximation
- Trailing number of 0s in product of two factorials
- Find the unit place digit of sum of N factorials
- Check if a given number divides the sum of the factorials of its digits
- Print factorials of a range in right aligned format
- Numbers less than N which are product of exactly two distinct prime numbers
- Print N lines of 4 numbers such that every pair among 4 numbers has a GCD K
- Count numbers which are divisible by all the numbers from 2 to 10
- Count numbers which can be constructed using two numbers
- Maximum sum of distinct numbers such that LCM of these numbers is N
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Improved By : jit_t