Count natural numbers whose factorials are divisible by x but not y
Given two numbers x and y (x <= y), find out the total number of natural numbers, say i, for which i! is divisible by x but not y.
Examples :
Input : x = 2, y = 5 Output : 3 There are three numbers, 2, 3 and 4 whose factorials are divisible by x but not y. Input: x = 15, y = 25 Output: 5 5! = 120 % 15 = 0 && 120 % 25 != 0 6! = 720 % 15 = 0 && 720 % 25 != 0 7! = 5040 % 15 = 0 && 5040 % 25 != 0 8! = 40320 % 15 = 0 && 40320 % 25 != 0 9! = 362880 % 15 = 0 && 362880 % 25 != 0 So total count = 5 Input: x = 10, y = 15 Output: 0
For all numbers greater than or equal to y, their factorials are divisible by y. So all natural numbers to be counted must be less than y.
A simple solution is to iterate from 1 to y-1 and for every number i check if i! is divisible by x and not divisible by y. If we apply this naive approach, we wouldn’t go above 20! or 21! (long long int will have its upper limit)
A better solution is based on below post.
Find the first natural number whose factorial is divisible by x
We find the first natural numbers whose factorials are divisible by x! and y! using above approach. Let the first natural numbers whose factorials are divisible by x and y be xf and yf respectively. Our final answer would be yf – xf. This formula is based on the fact that if i! is divisible by a number x, then (i+1)!, (i+2)!, … are also divisible by x.
Below is the implementation.
C++
// C++ program to count natural numbers whose // factorials are divisible by x but not y. #include<bits/stdc++.h> using namespace std; // GCD function to compute the greatest // divisor among a and b int gcd( int a, int b) { if ((a % b) == 0) return b; return gcd(b, a % b); } // Returns first number whose factorial // is divisible by x. int firstFactorialDivisibleNumber( int x) { int i = 1; // Result int new_x = x; for (i=1; i<x; i++) { // Remove common factors new_x /= gcd(i, new_x); // We found first i. if (new_x == 1) break ; } return i; } // Count of natural numbers whose factorials // are divisible by x but not y. int countFactorialXNotY( int x, int y) { // Return difference between first natural // number whose factorial is divisible by // y and first natural number whose factorial // is divisible by x. return (firstFactorialDivisibleNumber(y) - firstFactorialDivisibleNumber(x)); } // Driver code int main( void ) { int x = 15, y = 25; cout << countFactorialXNotY(x, y); return 0; } |
Java
// Java program to count natural numbers whose // factorials are divisible by x but not y. class GFG { // GCD function to compute the greatest // divisor among a and b static int gcd( int a, int b) { if ((a % b) == 0 ) return b; return gcd(b, a % b); } // Returns first number whose factorial // is divisible by x. static int firstFactorialDivisibleNumber( int x) { int i = 1 ; // Result int new_x = x; for (i = 1 ; i < x; i++) { // Remove common factors new_x /= gcd(i, new_x); // We found first i. if (new_x == 1 ) break ; } return i; } // Count of natural numbers whose factorials // are divisible by x but not y. static int countFactorialXNotY( int x, int y) { // Return difference between first natural // number whose factorial is divisible by // y and first natural number whose factorial // is divisible by x. return (firstFactorialDivisibleNumber(y) - firstFactorialDivisibleNumber(x)); } // Driver code public static void main (String[] args) { int x = 15 , y = 25 ; System.out.print(countFactorialXNotY(x, y)); } } // This code is contributed by Anant Agarwal. |
Python3
# Python program to count natural # numbers whose factorials are # divisible by x but not y. # GCD function to compute the greatest # divisor among a and b def gcd(a, b): if ((a % b) = = 0 ): return b return gcd(b, a % b) # Returns first number whose factorial # is divisible by x. def firstFactorialDivisibleNumber(x): # Result i = 1 new_x = x for i in range ( 1 , x): # Remove common factors new_x / = gcd(i, new_x) # We found first i. if (new_x = = 1 ): break return i # Count of natural numbers whose # factorials are divisible by x but # not y. def countFactorialXNotY(x, y): # Return difference between first # natural number whose factorial # is divisible by y and first # natural number whose factorial # is divisible by x. return (firstFactorialDivisibleNumber(y) - firstFactorialDivisibleNumber(x)) # Driver code x = 15 y = 25 print (countFactorialXNotY(x, y)) # This code is contributed by Anant Agarwal. |
C#
// C# program to count natural numbers whose // factorials are divisible by x but not y. using System; class GFG { // GCD function to compute the greatest // divisor among a and b static int gcd( int a, int b) { if ((a % b) == 0) return b; return gcd(b, a % b); } // Returns first number whose factorial // is divisible by x. static int firstFactorialDivisibleNumber( int x) { int i = 1; // Result int new_x = x; for (i = 1; i < x; i++) { // Remove common factors new_x /= gcd(i, new_x); // We found first i. if (new_x == 1) break ; } return i; } // Count of natural numbers whose factorials // are divisible by x but not y. static int countFactorialXNotY( int x, int y) { // Return difference between first natural // number whose factorial is divisible by // y and first natural number whose factorial // is divisible by x. return (firstFactorialDivisibleNumber(y) - firstFactorialDivisibleNumber(x)); } // Driver code public static void Main () { int x = 15, y = 25; Console.Write(countFactorialXNotY(x, y)); } } // This code is contributed by nitin mittal. |
PHP
<?php // PHP program to count natural // numbers whose factorials are // divisible by x but not y. // GCD function to compute the // greatest divisor among a and b function gcd( $a , $b ) { if (( $a % $b ) == 0) return $b ; return gcd( $b , $a % $b ); } // Returns first number whose // factorial is divisible by x. function firstFactorialDivisibleNumber( $x ) { // Result $i = 1; $new_x = $x ; for ( $i = 1; $i < $x ; $i ++) { // Remove common factors $new_x /= gcd( $i , $new_x ); // We found first i. if ( $new_x == 1) break ; } return $i ; } // Count of natural numbers // whose factorials are divisible // by x but not y. function countFactorialXNotY( $x , $y ) { // Return difference between // first natural number whose // factorial is divisible by // y and first natural number // whose factorial is divisible by x. return (firstFactorialDivisibleNumber( $y ) - firstFactorialDivisibleNumber( $x )); } // Driver code $x = 15; $y = 25; echo (countFactorialXNotY( $x , $y )); // This code is contributed by Ajit. ?> |
Javascript
<script> // Javascript program to Merge two sorted halves of // array Into Single Sorted Array // GCD function to compute the greatest // divisor among a and b function gcd(a, b) { if ((a % b) == 0) return b; return gcd(b, a % b); } // Returns first number whose factorial // is divisible by x. function firstFactorialDivisibleNumber(x) { let i = 1; // Result let new_x = x; for (i = 1; i < x; i++) { // Remove common factors new_x /= gcd(i, new_x); // We found first i. if (new_x == 1) break ; } return i; } // Count of natural numbers whose factorials // are divisible by x but not y. function countFactorialXNotY(x, y) { // Return difference between first natural // number whose factorial is divisible by // y and first natural number whose factorial // is divisible by x. return (firstFactorialDivisibleNumber(y) - firstFactorialDivisibleNumber(x)); } // Driver code let x = 15, y = 25; document.write(countFactorialXNotY(x, y)); </script> |
Output :
5
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