Given a tree, and the weights of all the nodes, the task is to count the number of nodes whose weight is prime.
Only the weights of the nodes 1 and 3 are prime.
Approach: Perform dfs on the tree and for every node, check if it’s weight is prime or not.
Below is the implementation of above approach:
- Count the nodes in the given tree whose weight is even
- Count the nodes in the given tree whose weight is a power of two
- Count the nodes in the given tree whose sum of digits of weight is odd
- Count the nodes in the given tree whose weight is even parity
- Count the nodes whose weight is a perfect square
- Count number of paths whose weight is exactly X and has at-least one edge of weight M
- Count of Prime Nodes of a Singly Linked List
- Count Non-Leaf nodes in a Binary Tree
- Determine the count of Leaf nodes in an N-ary tree
- Count the number of nodes at given level in a tree using BFS.
- Count the number of nodes at a given level in a tree using DFS
- Count the nodes of the given tree whose weighted string is a palindrome
- Count nodes with two children at level L in a Binary Tree
- Count the nodes of the tree whose weighted string contains a vowel
- Program to count leaf nodes in a binary tree
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.