Given two line segments AB and CD having A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4). The task is to check whether these two lines are orthogonal or not. Two lines are called orthogonal if they are perpendicular at the point of intersection.
Input: x1 = 0, y1 = 3, x2 = 0, y2 = -5 x3 = 2, y3 = 0, x4 = -1, y4 = 0 Output: Yes Input: x1 = 0, y1 = 4, x2 = 0, y2 = -9 x3 = 2, y3 = 0, x4 = -1, y4 = 0 Output: Yes
Approach: If the slopes of the two lines are m1 and m2 then for them to be orthogonal we need to check if:
- Both lines have infinite slope then answer is no.
- One line has infinite slope and if other line has 0 slope then answer is yes otherwise no.
- Both lines have finite slope and their product is -1 then the answer is yes.
Below is the implementation of the above approach:
- Check if given two straight lines are identical or not
- Check if three straight lines are concurrent or not
- Count of different straight lines with total n points with m collinear
- Check whether a given matrix is orthogonal or not
- Check if it is possible to draw a straight line with the given direction cosines
- Represent a given set of points by the best possible straight line
- Length of the normal from origin on a straight line whose intercepts are given
- Area of triangle formed by the axes of co-ordinates and a given straight line
- Distance between two parallel lines
- Minimum lines to cover all points
- Program for Point of Intersection of Two Lines
- Maximum points of intersection n lines
- Equation of straight line passing through a given point which bisects it into two equal line segments
- Pizza cut problem (Or Circle Division by Lines)
- Non-crossing lines to connect points in a circle
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.