Check whether a given number N is a Nude Number or not

Given an integer N, the task is to check whether N is a Nude number or not.

A Nude number is a number that is divisible by all of its digits (which should be nonzero). 

Example: 

Input: N = 672 
Output: Yes 
Explanation:
Since, 672 is divisible by all of its three digits 6, 7 and 2. Therefore the output is Yes.

Input: N = 450 
Output: No 
Explanation:
Since, 450 is not divisible by 0 (Also it gives exception). Therefore the output is No. 

Approach: Extract digits from number one by one and check these two conditions: 

1. The digit must be non-zero, to avoid exception
2. And the digit must divide the number N

When both these condition is satisfied by all digits of N, then the number is called Nude number.
Below is the implementation of the above approach:

C++

// C++ program to check if the
// number if Nude number or not

#include <iostream>
using namespace std;

// Check if all digits
// of num divide num
bool checkDivisbility(int num)
{
    // array to store all digits
    // of the given number
    int digit;
    int N = num;
    while (num != 0) {
        digit = num % 10;
        num = num / 10;

        // If any of the condition
        // is true for any digit
        // Then N is not a nude number
        if (digit == 0 || N % digit != 0)
            return false;
    }

    return true;
}

// Driver code
int main()
{
    int N = 128;

    bool result = checkDivisbility(N);
    if (result)
        cout << "Yes";
    else
        cout << "No";

    return 0;
}

Java

// Java program to check if the
// number if Nude number or not
import java.util.*;
class GFG{

// Check if all digits
// of num divide num
static boolean checkDivisbility(int num)
{
    // array to store all digits
    // of the given number
    int digit;
    int N = num;
    while (num != 0)
    {
        digit = num % 10;
        num = num / 10;

        // If any of the condition
        // is true for any digit
        // Then N is not a nude number
        if (digit == 0 || N % digit != 0)
            return false;
    }
    return true;
}

// Driver code
public static void main(String[] args)
{
    int N = 128;

    boolean result = checkDivisbility(N);
    if (result)
        System.out.print("Yes");
    else
        System.out.print("No");
}
}

// This code is contributed by 29AjayKumar

Python3

# Python3 program to check if the
# number if nude number or not

# Check if all digits
# of num divide num
def checkDivisbility(num):

    # Array to store all digits
    # of the given number
    digit = 0
    N = num

    while (num != 0):
        digit = num % 10
        num = num // 10

        # If any of the condition
        # is true for any digit
        # then N is not a nude number
        if (digit == 0 or N % digit != 0):
            return False

    return True

# Driver code
if __name__ == '__main__':

    N = 128

    result = checkDivisbility(N)
    if (result):
        print("Yes")
    else:
        print("No")

# This code is contributed by mohit kumar 29

C#

// C# program to check if the
// number if Nude number or not
using System;
class GFG{

// Check if all digits
// of num divide num
static bool checkDivisbility(int num)
{
    // array to store all digits
    // of the given number
    int digit;
    int N = num;
    while (num != 0)
    {
        digit = num % 10;
        num = num / 10;

        // If any of the condition
        // is true for any digit
        // Then N is not a nude number
        if (digit == 0 || N % digit != 0)
            return false;
    }
    return true;
}

// Driver code
public static void Main()
{
    int N = 128;

    bool result = checkDivisbility(N);
    if (result)
        Console.Write("Yes");
    else
        Console.Write("No");
}
}

// This code is contributed by Nidhi_biet

Javascript

<script>

// Javascript program to check if the
// number if Nude number or not

// Check if all digits
// of num divide num
function checkDivisbility(num)
{
    // array to store all digits
    // of the given number
    let digit;
    let N = num;
    while (num != 0) {
        digit = num % 10;
        num = Math.floor(num / 10);

        // If any of the condition
        // is true for any digit
        // Then N is not a nude number
        if (digit == 0 || N % digit != 0)
            return false;
    }

    return true;
}

// Driver code

    let N = 128;

    let result = checkDivisbility(N);
    if (result)
        document.write("Yes");
    else
        document.write("No");

// This code is contributed by Mayank Tyagi

</script>

Output:

Yes

Time complexity: O( log₁₀ N ), where N is the given integer.
Auxiliary space: O(1) as constant space is being used.