# Check whether a given number is an ugly number or not

Given an integer N, the task is to find out whether the given number is an Ugly number or not .

Ugly numbers are numbers whose only prime factors are 2, 3 or 5.

Examples:

Input: N = 14
Output: No
Explanation:
14 is not ugly since it includes another prime factor 7.

Input: N = 6
Output: Yes
Explanation:
6 is a ugly since it includes 2 and 3.

Approach: The idea is to use recursion to solve this problem and check if a number is divisible by 2,  3 or 5. If yes then divide the number by that and recursively check that a number is an ugly number or not. If at any time, there is no such divisor, then return false, else true.

Below is the implementation of the above approach:

## C++

 `// C++ implementation to check ` `// if a number is an ugly ` `// number or not ` ` `  `#include ` `#include ` ` `  `// Function to check if a number ` `// is an ugly number or not ` `int` `isUgly(``int` `n) ` `{ ` `    ``// Base Cases ` `    ``if` `(n == 1) ` `        ``return` `1; ` `    ``if` `(n <= 0) ` `        ``return` `0; ` ` `  `    ``// Condition to check if the ` `    ``// number is divided by 2, 3, or 5 ` `    ``if` `(n % 2 == 0) { ` `        ``return` `(isUgly(n / 2)); ` `    ``} ` `    ``if` `(n % 3 == 0) { ` `        ``return` `(isUgly(n / 3)); ` `    ``} ` `    ``if` `(n % 5 == 0) { ` `        ``return` `(isUgly(n / 5)); ` `    ``} ` ` `  `    ``// Otherwise return false ` `    ``return` `0; ` `} ` `// Driver Code ` `int` `main() ` `{ ` `    ``int` `no = isUgly(14); ` `    ``if` `(no == 1) ` `        ``printf``(``"Yes"``); ` `    ``else` `        ``printf``(``"No"``); ` `    ``return` `0; ` `} `

## Java

 `// Java implementation to ` `// check if a number is ugly number ` `class` `GFG { ` ` `  `    ``// Function to check the ugly ` `    ``// number ` `    ``static` `int` `isUgly(``int` `n) ` `    ``{ ` `        ``// Base Cases ` `        ``if` `(n == ``1``) ` `            ``return` `1``; ` `        ``if` `(n <= ``0``) ` `            ``return` `0``; ` ` `  `        ``// Condition to check if ` `        ``// a number is divide by ` `        ``// 2, 3, or 5 ` `        ``if` `(n % ``2` `== ``0``) { ` `            ``return` `(isUgly(n / ``2``)); ` `        ``} ` `        ``if` `(n % ``3` `== ``0``) { ` `            ``return` `(isUgly(n / ``3``)); ` `        ``} ` `        ``if` `(n % ``5` `== ``0``) { ` `            ``return` `(isUgly(n / ``5``)); ` `        ``} ` `        ``return` `0``; ` `    ``} ` ` `  `    ``// Driver Code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `no = isUgly(``14``); ` `        ``if` `(no == ``1``) ` `            ``System.out.println(``"Yes"``); ` `        ``else` `            ``System.out.println(``"No"``); ` `    ``} ` `} `

## Python3

 `# Python3 implementation to check ` `# if a number is an ugly number  ` `# or not ` ` `  `# Function to check if a number ` `# is an ugly number or not ` `def` `isUgly(n): ` ` `  `    ``# Base Cases ` `    ``if` `(n ``=``=` `1``): ` `        ``return` `1` `    ``if` `(n <``=` `0``): ` `        ``return` `0` ` `  `    ``# Condition to check if the ` `    ``# number is divided by 2, 3, or 5 ` `    ``if` `(n ``%` `2` `=``=` `0``): ` `        ``return` `(isUgly(n ``/``/` `2``)) ` `         `  `    ``if` `(n ``%` `3` `=``=` `0``): ` `        ``return` `(isUgly(n ``/``/` `3``)) ` `     `  `    ``if` `(n ``%` `5` `=``=` `0``): ` `        ``return` `(isUgly(n ``/``/` `5``)) ` ` `  `    ``# Otherwise return false ` `    ``return` `0` ` `  `# Driver Code ` `if` `__name__ ``=``=` `"__main__"``: ` ` `  `    ``no ``=` `isUgly(``14``) ` `     `  `    ``if` `(no ``=``=` `1``): ` `        ``print``(``"Yes"``) ` `    ``else``: ` `        ``print``(``"No"``) ` ` `  `# This code is contributed by chitranayal `

## C#

 `// C# implementation to check  ` `// if a number is ugly number ` `using` `System; ` ` `  `class` `GFG{ ` ` `  `// Function to check the ugly ` `// number ` `static` `int` `isUgly(``int` `n) ` `{ ` `     `  `    ``// Base Cases ` `    ``if` `(n == 1) ` `        ``return` `1; ` `    ``if` `(n <= 0) ` `        ``return` `0; ` ` `  `    ``// Condition to check if ` `    ``// a number is divide by ` `    ``// 2, 3, or 5 ` `    ``if` `(n % 2 == 0) ` `    ``{ ` `        ``return` `(isUgly(n / 2)); ` `    ``} ` `    ``if` `(n % 3 == 0)  ` `    ``{ ` `        ``return` `(isUgly(n / 3)); ` `    ``} ` `    ``if` `(n % 5 == 0)  ` `    ``{ ` `        ``return` `(isUgly(n / 5)); ` `    ``} ` `    ``return` `0; ` `} ` ` `  `// Driver Code ` `public` `static` `void` `Main(String []args) ` `{ ` `    ``int` `no = isUgly(14); ` `     `  `    ``if` `(no == 1) ` `        ``Console.WriteLine(``"Yes"``); ` `    ``else` `        ``Console.WriteLine(``"No"``); ` `} ` `} ` ` `  `// This code is contributed by amal kumar choubey `

Output:

```No
```

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My Personal Notes arrow_drop_up before giving up , just think why u started

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