Check whether all the rotations of a given number is greater than or equal to the given number or not

Given an integer x, the task is to find if every k-cycle shift on the element produces a number greater than or equal to the same element.
A k-cyclic shift of an integer x is a function that removes the last k digits of x and inserts them in its beginning.
For example, the k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2. Print Yes if the given condition is satisfied else print No.

Examples:

Input: x = 123
Output : Yes
The k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2.
Both 312 and 231 are greater than 123.



Input: 2214
Output: No
The k-cyclic shift of 2214 when k=2 is 1422 which is smaller than 2214

Approach: Simply find all the possible k cyclic shifts of the number and check if all are greater than the given number or not.

Below is the implementation of the above approach:

C++

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// CPP implementation of the approach
#include<bits/stdc++.h>
using namespace std;
  
void CheckKCycles(int n, string s) 
{
    bool ff = true;
    int x = 0;
    for (int i = 1; i < n; i++) 
    {
  
        // Splitting the number at index i 
        // and adding to the front 
        x = (s.substr(i) + s.substr(0, i)).length();
  
        // Checking if the value is greater than 
        // or equal to the given value 
        if (x >= s.length()) 
        {
            continue;
        }
        ff = false;
        break;
    }
    if (ff) 
    {
        cout << ("Yes");
    }
    else
    {
        cout << ("No");
    }
}
  
// Driver code
int main() 
{
    int n = 3;
    string s = "123";
    CheckKCycles(n, s);
    return 0;
}
  
/* This code contributed by Rajput-Ji */

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Java














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// Java implementation of the approach 


class GFG  


{ 


  


    static void CheckKCycles(int n, String s)  


    { 


        boolean ff = true; 


        int x = 0; 


        for (int i = 1; i < n; i++)  


        { 


  


            // Splitting the number at index i  


            // and adding to the front  


            x = (s.substring(i) + s.substring(0, i)).length(); 


  


            // Checking if the value is greater than  


            // or equal to the given value  


            if (x >= s.length())  


            { 


                continue; 


            } 


            ff = false; 


            break; 


        } 


        if (ff)  


        { 


            System.out.println("Yes"); 


        } 


        else 


        { 


            System.out.println("No"); 


        } 


  


    } 


  


    // Driver code 


    public static void main(String[] args)  


    { 


        int n = 3; 


        String s = "123"; 


        CheckKCycles(n, s); 


    } 


} 


  


/* This code contributed by PrinciRaj1992 */



















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Python














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# Python3 implementation of the approach 


def CheckKCycles(n, s): 


    ff = True


    for i in range(1, n): 


  


        # Splitting the number at index i  


        # and adding to the front 


        x = int(s[i:] + s[0:i]) 


  


        # Checking if the value is greater than  


        # or equal to the given value 


        if (x >= int(s)): 


            continue


        ff = False


        break


    if (ff): 


        print("Yes") 


    else: 


        print("No") 


  


n = 3


s = "123"


CheckKCycles(n, s) 



















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C#














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// C# implementation of the approach 


using System; 


  


class GFG  


{ 


  


    static void CheckKCycles(int n, String s)  


    { 


        bool ff = true; 


        int x = 0; 


        for (int i = 1; i < n; i++)  


        { 


  


            // Splitting the number at index i  


            // and adding to the front  


            x = (s.Substring(i) + s.Substring(0, i)).Length; 


  


            // Checking if the value is greater than  


            // or equal to the given value  


            if (x >= s.Length)  


            { 


                continue; 


            } 


            ff = false; 


            break; 


        } 


        if (ff)  


        { 


            Console.WriteLine("Yes"); 


        } 


        else


        { 


            Console.WriteLine("No"); 


        } 


  


    } 


  


    // Driver code 


    public static void Main(String[] args)  


    { 


        int n = 3; 


        String s = "123"; 


        CheckKCycles(n, s); 


    } 


} 


  


// This code has been contributed by 29AjayKumar 



















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PHP














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<?php 


// PHP implementation of the approach 


  


function CheckKCycles($n, $s)  


{ 


    $ff = true; 


    $x = 0; 


    for ($i = 1; $i < $n; $i++)  


    { 


  


        // Splitting the number at index i  


        // and adding to the front  


        $x = strlen(substr($s, $i).substr($s, 0, $i)); 


  


        // Checking if the value is greater than  


        // or equal to the given value  


        if ($x >= strlen($s))  


        { 


            continue; 


        } 


        $ff = false; 


        break; 


    } 


    if ($ff)  


    { 


        print("Yes"); 


    } 


    else


    { 


        print("No"); 


    } 


} 


  


// Driver code 


$n = 3; 


$s = "123"; 


CheckKCycles($n, $s); 


  


// This code contributed by mits  


?> 



















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Output:


Yes






          
          
          

          

    

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