Second most repeated word in a sequence
Given a sequence of strings, the task is to find out the second most repeated (or frequent) string in the given sequence.(Considering no two words are the second most repeated, there will be always a single word).
Examples:
Input : {"aaa", "bbb", "ccc", "bbb",
"aaa", "aaa"}
Output : bbb
Input : {"geeks", "for", "geeks", "for",
"geeks", "aaa"}
Output : for
Asked in : Amazon
- Store all the words in a map with their occurrence with word as key and its occurrence as value.
- Find the second largest value in the map.
- Traverse the map again and return the word with occurrence value equals to second max value.
C++
// C++ program to find out the second // most repeated word #include <bits/stdc++.h> using namespace std; // Function to find the word string secMostRepeated(vector<string> seq) { // Store all the words with its occurrence unordered_map<string, int> occ; for (int i = 0; i < seq.size(); i++) occ[seq[i]]++; // find the second largest occurrence int first_max = INT_MIN, sec_max = INT_MIN; for (auto it = occ.begin(); it != occ.end(); it++) { if (it->second > first_max) { sec_max = first_max; first_max = it->second; } else if (it->second > sec_max && it->second != first_max) sec_max = it->second; } // Return string with occurrence equals // to sec_max for (auto it = occ.begin(); it != occ.end(); it++) if (it->second == sec_max) return it->first; } // Driver program int main() { vector<string> seq = { "ccc", "aaa", "ccc", "ddd", "aaa", "aaa" }; cout << secMostRepeated(seq); return 0; } |
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Java
// Java program to find out the second // most repeated word import java.util.*; class GFG { // Method to find the word static String secMostRepeated(Vector<String> seq) { // Store all the words with its occurrence HashMap<String, Integer> occ = new HashMap<String,Integer>(seq.size()){ @Override public Integer get(Object key) { return containsKey(key) ? super.get(key) : 0; } }; for (int i = 0; i < seq.size(); i++) occ.put(seq.get(i), occ.get(seq.get(i))+1); // find the second largest occurrence int first_max = Integer.MIN_VALUE, sec_max = Integer.MIN_VALUE; Iterator<Map.Entry<String, Integer>> itr = occ.entrySet().iterator(); while (itr.hasNext()) { Map.Entry<String, Integer> entry = itr.next(); int v = entry.getValue(); if( v > first_max) { sec_max = first_max; first_max = v; } else if (v > sec_max && v != first_max) sec_max = v; } // Return string with occurrence equals // to sec_max itr = occ.entrySet().iterator(); while (itr.hasNext()) { Map.Entry<String, Integer> entry = itr.next(); int v = entry.getValue(); if (v == sec_max) return entry.getKey(); } return null; } // Driver method public static void main(String[] args) { String arr[] = { "ccc", "aaa", "ccc", "ddd", "aaa", "aaa" }; List<String> seq = Arrays.asList(arr); System.out.println(secMostRepeated(new Vector<>(seq))); } } // This program is contributed by Gaurav Miglani |
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C#
// C# program to find out the second // most repeated word using System; using System.Collections.Generic; class GFG { // Method to find the word static String secMostRepeated(List<String> seq) { // Store all the words with its occurrence Dictionary<String, int> occ = new Dictionary<String, int>(); for (int i = 0; i < seq.Count; i++) if(occ.ContainsKey(seq[i])) occ[seq[i]] = occ[seq[i]] + 1; else occ.Add(seq[i], 1); // find the second largest occurrence int first_max = int.MinValue, sec_max = int.MinValue; foreach(KeyValuePair<String, int> entry in occ) { int v = entry.Value; if( v > first_max) { sec_max = first_max; first_max = v; } else if (v > sec_max && v != first_max) sec_max = v; } // Return string with occurrence equals // to sec_max foreach(KeyValuePair<String, int> entry in occ) { int v = entry.Value; if (v == sec_max) return entry.Key; } return null; } // Driver method public static void Main(String[] args) { String []arr = { "ccc", "aaa", "ccc", "ddd", "aaa", "aaa" }; List<String> seq = new List<String>(arr); Console.WriteLine(secMostRepeated(seq)); } } // This code is contributed by Rajput-Ji |
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Output:
ccc
Reference:
https://www.careercup.com/question?id=5748104113422336
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