Search an element in a Linked List (Iterative and Recursive)
Write a function that searches a given key ‘x’ in a given singly linked list. The function should return true if x is present in linked list and false otherwise.
bool search(Node *head, int x)
For example, if the key to be searched is 15 and linked list is 14->21->11->30->10, then function should return false. If key to be searched is 14, then the function should return true.
Iterative Solution
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1) Initialize a node pointer, current = head.
2) Do following while current is not NULL
a) current->key is equal to the key being searched return true.
b) current = current->next
3) Return false Following is iterative implementation of above algorithm to search a given key.
C++
// Iterative C++ program to search// an element in linked list#include <bits/stdc++.h>using namespace std;/* Link list node */class Node{ public: int key; Node* next;};/* Given a reference (pointer to pointer) to the headof a list and an int, push a new node on the frontof the list. */void push(Node** head_ref, int new_key){ /* allocate node */ Node* new_node = new Node(); /* put in the key */ new_node->key = new_key; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node;}/* Checks whether the value x is present in linked list */bool search(Node* head, int x){ Node* current = head; // Initialize current while (current != NULL) { if (current->key == x) return true; current = current->next; } return false;}/* Driver program to test count function*/int main(){ /* Start with the empty list */ Node* head = NULL; int x = 21; /* Use push() to construct below list 14->21->11->30->10 */ push(&head, 10); push(&head, 30); push(&head, 11); push(&head, 21); push(&head, 14); search(head, 21)? cout<<"Yes" : cout<<"No"; return 0;}// This is code is contributed by rathbhupendra |
C
// Iterative C program to search an element in linked list#include<stdio.h>#include<stdlib.h>#include<stdbool.h>/* Link list node */struct Node{ int key; struct Node* next;};/* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */void push(struct Node** head_ref, int new_key){ /* allocate node */ struct Node* new_node = (struct Node*) malloc(sizeof(struct Node)); /* put in the key */ new_node->key = new_key; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node;}/* Checks whether the value x is present in linked list */bool search(struct Node* head, int x){ struct Node* current = head; // Initialize current while (current != NULL) { if (current->key == x) return true; current = current->next; } return false;}/* Driver program to test count function*/int main(){ /* Start with the empty list */ struct Node* head = NULL; int x = 21; /* Use push() to construct below list 14->21->11->30->10 */ push(&head, 10); push(&head, 30); push(&head, 11); push(&head, 21); push(&head, 14); search(head, 21)? printf("Yes") : printf("No"); return 0;} |
Java
// Iterative Java program to search an element// in linked list//Node classclass Node{ int data; Node next; Node(int d) { data = d; next = null; }}//Linked list classclass LinkedList{ Node head; //Head of list //Inserts a new node at the front of the list public void push(int new_data) { //Allocate new node and putting data Node new_node = new Node(new_data); //Make next of new node as head new_node.next = head; //Move the head to point to new Node head = new_node; } //Checks whether the value x is present in linked list public boolean search(Node head, int x) { Node current = head; //Initialize current while (current != null) { if (current.data == x) return true; //data found current = current.next; } return false; //data not found } //Driver function to test the above functions public static void main(String args[]) { //Start with the empty list LinkedList llist = new LinkedList(); /*Use push() to construct below list 14->21->11->30->10 */ llist.push(10); llist.push(30); llist.push(11); llist.push(21); llist.push(14); if (llist.search(llist.head, 21)) System.out.println("Yes"); else System.out.println("No"); }}// This code is contributed by Pratik Agarwal |
Python
# Iterative Python program to search an element# in linked list# Node classclass Node: # Function to initialise the node object def __init__(self, data): self.data = data # Assign data self.next = None # Initialize next as null# Linked List classclass LinkedList: def __init__(self): self.head = None # Initialize head as None # This function insert a new node at the # beginning of the linked list def push(self, new_data): # Create a new Node new_node = Node(new_data) # 3. Make next of new Node as head new_node.next = self.head # 4. Move the head to point to new Node self.head = new_node # This Function checks whether the value # x present in the linked list def search(self, x): # Initialize current to head current = self.head # loop till current not equal to None while current != None: if current.data == x: return True # data found current = current.next return False # Data Not found# Code execution starts hereif __name__ == '__main__': # Start with the empty list llist = LinkedList() ''' Use push() to construct below list 14->21->11->30->10 ''' llist.push(10); llist.push(30); llist.push(11); llist.push(21); llist.push(14); if llist.search(21): print("Yes") else: print("No")# This code is contributed by Ravi Shankar |
C#
// Iterative C# program to search an element// in linked listusing System;// Node classpublic class Node{ public int data; public Node next; public Node(int d) { data = d; next = null; }}// Linked list classpublic class LinkedList{ Node head; // Head of list // Inserts a new node at the front of the list public void push(int new_data) { // Allocate new node and putting data Node new_node = new Node(new_data); // Make next of new node as head new_node.next = head; // Move the head to point to new Node head = new_node; } // Checks whether the value x is present in linked list public bool search(Node head, int x) { Node current = head; // Initialize current while (current != null) { if (current.data == x) return true; // data found current = current.next; } return false; // data not found } // Driver code public static void Main(String []args) { // Start with the empty list LinkedList llist = new LinkedList(); /*Use push() to construct below list 14->21->11->30->10 */ llist.push(10); llist.push(30); llist.push(11); llist.push(21); llist.push(14); if (llist.search(llist.head, 21)) Console.WriteLine("Yes"); else Console.WriteLine("No"); }}// This code contributed by Rajput-Ji |
Javascript
<script>// Iterative javascript program// to search an element// in linked list//Node classclass Node { constructor(d) { this.data = d; this.next = null; }}// Linked list class var head; // Head of list // Inserts a new node at the front of the list function push(new_data) { // Allocate new node and putting data var new_node = new Node(new_data); // Make next of new node as head new_node.next = head; // Move the head to point to new Node head = new_node; } // Checks whether the value // x is present in linked list function search( head , x) { var current = head; // Initialize current while (current != null) { if (current.data == x) return true; // data found current = current.next; } return false; // data not found } // Driver function to test // the above functions // Start with the empty list /* Use push() to construct below list 14->21->11->30->10 */ push(10); push(30); push(11); push(21); push(14); if (search(head, 21)) document.write("Yes"); else document.write("No");// This code contributed by aashish1995</script> |
Output:
Yes
Recursive Solution
bool search(head, x) 1) If head is NULL, return false. 2) If head's key is same as x, return true; 3) Else return search(head->next, x)
Following is the recursive implementation of the above algorithm to search a given key.
C++
// Recursive C++ program to search// an element in linked list#include <bits/stdc++.h>using namespace std;/* Link list node */struct Node{ int key; struct Node* next;};/* Given a reference (pointer to pointer) to the headof a list and an int, push a new node on the frontof the list. */void push(struct Node** head_ref, int new_key){ /* allocate node */ struct Node* new_node = (struct Node*) malloc(sizeof(struct Node)); /* put in the key */ new_node->key = new_key; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node;}/* Checks whether the value x is present in linked list */bool search(struct Node* head, int x){ // Base case if (head == NULL) return false; // If key is present in current node, return true if (head->key == x) return true; // Recur for remaining list return search(head->next, x);}/* Driver code*/int main(){ /* Start with the empty list */ struct Node* head = NULL; int x = 21; /* Use push() to construct below list 14->21->11->30->10 */ push(&head, 10); push(&head, 30); push(&head, 11); push(&head, 21); push(&head, 14); search(head, 21)? cout << "Yes" : cout << "No"; return 0;}// This code is contributed by SHUBHAMSINGH10 |
C
// Recursive C program to search an element in linked list#include<stdio.h>#include<stdlib.h>#include<stdbool.h>/* Link list node */struct Node{ int key; struct Node* next;};/* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */void push(struct Node** head_ref, int new_key){ /* allocate node */ struct Node* new_node = (struct Node*) malloc(sizeof(struct Node)); /* put in the key */ new_node->key = new_key; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node;}/* Checks whether the value x is present in linked list */bool search(struct Node* head, int x){ // Base case if (head == NULL) return false; // If key is present in current node, return true if (head->key == x) return true; // Recur for remaining list return search(head->next, x);}/* Driver program to test count function*/int main(){ /* Start with the empty list */ struct Node* head = NULL; int x = 21; /* Use push() to construct below list 14->21->11->30->10 */ push(&head, 10); push(&head, 30); push(&head, 11); push(&head, 21); push(&head, 14); search(head, 21)? printf("Yes") : printf("No"); return 0;} |
Java
// Recursive Java program to search an element// in linked list// Node classclass Node{ int data; Node next; Node(int d) { data = d; next = null; }}// Linked list classclass LinkedList{ Node head; //Head of list //Inserts a new node at the front of the list public void push(int new_data) { //Allocate new node and putting data Node new_node = new Node(new_data); //Make next of new node as head new_node.next = head; //Move the head to point to new Node head = new_node; } // Checks whether the value x is present // in linked list public boolean search(Node head, int x) { // Base case if (head == null) return false; // If key is present in current node, // return true if (head.data == x) return true; // Recur for remaining list return search(head.next, x); } // Driver function to test the above functions public static void main(String args[]) { // Start with the empty list LinkedList llist = new LinkedList(); /* Use push() to construct below list 14->21->11->30->10 */ llist.push(10); llist.push(30); llist.push(11); llist.push(21); llist.push(14); if (llist.search(llist.head, 21)) System.out.println("Yes"); else System.out.println("No"); }}// This code is contributed by Pratik Agarwal |
Python
# Recursive Python program to# search an element in linked list# Node classclass Node: # Function to initialise # the node object def __init__(self, data): self.data = data # Assign data self.next = None # Initialize next as nullclass LinkedList: def __init__(self): self.head = None # Initialize head as None # This function insert a new node at # the beginning of the linked list def push(self, new_data): # Create a new Node new_node = Node(new_data) # Make next of new Node as head new_node.next = self.head # Move the head to # point to new Node self.head = new_node # Checks whether the value key # is present in linked list def search(self, li, key): # Base case if(not li): return False # If key is present in # current node, return true if(li.data == key): return True # Recur for remaining list return self.search(li.next, key) # Driver Code if __name__=='__main__': li = LinkedList() li.push(1) li.push(2) li.push(3) li.push(4) key = 4 if li.search(li.head,key): print("Yes") else: print("No") # This code is contributed# by Manoj Sharma |
C#
// Recursive C# program to search// an element in linked listusing System;// Node classpublic class Node{ public int data; public Node next; public Node(int d) { data = d; next = null; }}// Linked list classpublic class LinkedList{ Node head; //Head of list //Inserts a new node at the front of the list public void push(int new_data) { //Allocate new node and putting data Node new_node = new Node(new_data); //Make next of new node as head new_node.next = head; //Move the head to point to new Node head = new_node; } // Checks whether the value x is present // in linked list public bool search(Node head, int x) { // Base case if (head == null) return false; // If key is present in current node, // return true if (head.data == x) return true; // Recur for remaining list return search(head.next, x); } // Driver code public static void Main() { // Start with the empty list LinkedList llist = new LinkedList(); /* Use push() to construct below list 14->21->11->30->10 */ llist.push(10); llist.push(30); llist.push(11); llist.push(21); llist.push(14); if (llist.search(llist.head, 21)) Console.WriteLine("Yes"); else Console.WriteLine("No"); }}// This code is contributed by PrinciRaj1992 |
Javascript
<script>// Recursive javascript program to search an element// in linked list// Node class class Node { constructor(val) { this.data = val; this.next = null; } } // Linked list classvar head; // Head of list // Inserts a new node at the front of the list function push(new_data) { // Allocate new node and putting datavar new_node = new Node(new_data); // Make next of new node as head new_node.next = head; // Move the head to point to new Node head = new_node; } // Checks whether the value x is present // in linked list function search(head , x) { // Base case if (head == null) return false; // If key is present in current node, // return true if (head.data == x) return true; // Recur for remaining list return search(head.next, x); } // Driver function to test the above functions // Start with the empty list /* * Use push() to construct below list 14->21->11->30->10 */ push(10); push(30); push(11); push(21); push(14); if (search(head, 21)) document.write("Yes"); else document.write("No");// This code contributed by gauravrajput1</script> |
Output:
Yes
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