# hex() function in Python

• Difficulty Level : Easy
• Last Updated : 27 Oct, 2021

hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.

Syntax :

```hex(x)
Parameters :
x - an integer number (int object)
Returns :  Returns hexadecimal string.```

Errors and Exceptions :

```TypeError :  Returns TypeError when anything other than
integer type constants are passed as parameters.```

Code #1 : Illustrates use of hex() function.

## Python3

 `# Python3 program to illustrate``# hex() function` `print``(``"The hexadecimal form of 23 is "``                            ``+` `hex``(``23``))``                            ` `print``(``"The hexadecimal form of the "``      ``"ascii value is 'a' is "` `+` `hex``(``ord``(``'a'``)))``      ` `print``(``"The hexadecimal form of 3.9 is "``                        ``+` `float``.``hex``(``3.9``))`

Output :

```The hexadecimal form of 23 is 0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1```

Code #2: Demonstrate TypeError when floating point values are passed as parameter.

## Python3

 `# hex() accepts only integer values as parameters``print``(``"The hexadecimal form of 11.1 is "``                            ``+` `hex``(``11.1``))` `'''``# The hexadecimal conversion of floating ``# point integers can be done using the``# function float.hex()``print("The hexadecimal form of 11.1 is "``                    ``+ float.hex(11.1))``# Output :``# The hexadecimal form of 11.1 is 0x1.6333333333333p+3` `# Similarly, float.hex() throws a TypeError``# when integer values are passed in it.``'''`

Output :

```Traceback (most recent call last):
File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in
print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer```

Applications :
hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.

Code #3 :

## Python3

 `# TypeConversion from decimal with base 10``# to hexadecimal form with base 16`  `# Taking input from user``# an integer with base 10``number ``=` `int``(``input``(``"Enter a number with base 10\n"``))` `# The choices present to the user``print``(``"a. Decimal to Hexadecimal "``)``print``(``"b. Decimal to Octal"``)``print``(``"c. Decimal to Binary"``)` `# taking user input``print``(``"Enter your choice :- "``)``choice ``=` `input``()` `# Running a variable choice``# Hexadecimal form if choice``# is set to 'a'``if` `choice ``is` `'a'``:` `    ``# lstrip helps remove "0x" from the left``    ``# rstrip helps remove "L" from the right,``    ``# L represents a long number``    ``print``(``"Hexadecimal form of "` `+` `str``(number) ``+``        ``" is "` `+` `hex``(number).lstrip(``"0x"``).rstrip(``"L"``))``        ` `if` `choice ``is` `'b'``:``    ` `    ``# Octal representation is done``    ``# by adding a prefix "0o"``    ``print``(``"Octal form of "` `+` `str``(number) ``+``        ``" is "` `+` `oct``(number).lstrip(``"0o"``).rstrip(``"L"``))``        ` `if` `choice ``is` `'c'``:``    ` `    ``# Binary representation is done by``    ``# the addition of prefix "0b"``    ``print``(``"Binary form of "` `+` `str``(number) ``+``        ``" is "``+``bin``(number).lstrip(``"0b"``).rstrip(``"L"``))`

Output :

input variant a)

```Enter a number with base 10
123
a. Decimal to Hexadecimal
b. Decimal to Octal
c. Decimal to Binary
a
Hexadecimal form of 123 is 7b```

input variant b)

```Enter a number with base 10
123456789
a. Decimal to Hexadecimal
b. Decimal to Octal
c. Decimal to Binary