Python | hex() function

hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.

Syntax :

hex(x) 
Parameters : 
x - an integer number (int object)
Returns :  Returns hexadecimal string.

Errors and Exceptions :

TypeError :  Returns TypeError when anything other than
             integer type constants are passed as parameters.

 
Code #1 : Illustrates use of hex() function.

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# Python3 program to illustrate
# hex() function
  
print("The hexadecimal form of 23 is"
                            + hex(23))
                              
print("The hexadecimal form of the "
      "ascii value is 'a' is " + hex(ord('a')))
        
print("The hexadecimal form of 3.9 is "
                        + float.hex(3.9))

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Output :

The hexadecimal form of 23 is0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1

 
Code #2: Demontsrate TypeError when floating point values are passed as parameter.

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# hex() accepts only integer vaues as parameters
print("The hexadecimal form of 11.1 is "
                            + hex(11.1))
  
'''
# The hexadecimal conversion of floating  
# point integers can be done using the
# function float.hex()
print("The hexadecimal form of 11.1 is " 
                    + float.hex(11.1))
# Output :
# The hexadecimal form of 11.1 is 0x1.6333333333333p+3
  
# Similarly, float.hex() throws a TypeError
# when integer values are passed in it. 
'''

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Output :

Traceback (most recent call last):
  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in 
    print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer

 
Applications :
hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.

Code #3 :

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# TypeConversion from decimal with base 10 
# to hexadecimal form with base 16
  
  
# Taking input from user 
# an integr with base 10
number = int(input("Enter a number with base 10\n"))
  
# The choices present to the user
print("a. Decimal to Hexadecimal ")
print("b. Decimal to Octal")
print("c. Decimal to Binary")
  
# taking user input
print("Enter your choice :- ")
choice = input()
  
# Running a variable choice
# Hexadecimal form if choice
# is set to 'a'
if choice is 'a':
  
    # lstrip helps remove "0x" from the left 
    # rstrip helps remove "L" from the right,
    # L represents a long number
    print("Hexadecimal form of " + str(number) + 
        " is " + hex(number).lstrip("0x").rstrip("L"))
          
if choice is 'b':
      
    # Octal representation is done
    # by adding a prefix "0o" 
    print("Octal form of " + str(number) +
        " is " + oct(number).lstrip("0o").rstrip("L"))
          
if choice is 'c':
      
    # Binary representation is done by
    # the addition of prefix "0b"
    print("Binary form of " + str(number) + 
        " is "+bin(number).lstrip("0b").rstrip("L"))

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Output :

Enter a number with base 10
123
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice :- 
a
Hexadecimal form of 123 is 7b
Enter a number with base 10
123456789
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice :- 
a
Hexadecimal form of 123456789 is 75bcd15


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