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hex() function in Python

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  • Difficulty Level : Easy
  • Last Updated : 27 Oct, 2021

hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.

Syntax : 

hex(x) 
Parameters : 
x - an integer number (int object)
Returns :  Returns hexadecimal string.

Errors and Exceptions : 

TypeError :  Returns TypeError when anything other than
             integer type constants are passed as parameters.

  
Code #1 : Illustrates use of hex() function. 

Python3




# Python3 program to illustrate
# hex() function
 
print("The hexadecimal form of 23 is "
                            + hex(23))
                             
print("The hexadecimal form of the "
      "ascii value is 'a' is " + hex(ord('a')))
       
print("The hexadecimal form of 3.9 is "
                        + float.hex(3.9))

Output : 

The hexadecimal form of 23 is 0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1

Code #2: Demonstrate TypeError when floating point values are passed as parameter. 

Python3




# hex() accepts only integer values as parameters
print("The hexadecimal form of 11.1 is "
                            + hex(11.1))
 
'''
# The hexadecimal conversion of floating 
# point integers can be done using the
# function float.hex()
print("The hexadecimal form of 11.1 is "
                    + float.hex(11.1))
# Output :
# The hexadecimal form of 11.1 is 0x1.6333333333333p+3
 
# Similarly, float.hex() throws a TypeError
# when integer values are passed in it.
'''

Output : 

Traceback (most recent call last):
  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in 
    print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer

  
Applications : 
hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.
 

Code #3 : 

Python3




# TypeConversion from decimal with base 10
# to hexadecimal form with base 16
 
 
# Taking input from user
# an integer with base 10
number = int(input("Enter a number with base 10\n"))
 
# The choices present to the user
print("a. Decimal to Hexadecimal ")
print("b. Decimal to Octal")
print("c. Decimal to Binary")
 
# taking user input
print("Enter your choice :- ")
choice = input()
 
# Running a variable choice
# Hexadecimal form if choice
# is set to 'a'
if choice is 'a':
 
    # lstrip helps remove "0x" from the left
    # rstrip helps remove "L" from the right,
    # L represents a long number
    print("Hexadecimal form of " + str(number) +
        " is " + hex(number).lstrip("0x").rstrip("L"))
         
if choice is 'b':
     
    # Octal representation is done
    # by adding a prefix "0o"
    print("Octal form of " + str(number) +
        " is " + oct(number).lstrip("0o").rstrip("L"))
         
if choice is 'c':
     
    # Binary representation is done by
    # the addition of prefix "0b"
    print("Binary form of " + str(number) +
        " is "+bin(number).lstrip("0b").rstrip("L"))

Output : 

input variant a)

Enter a number with base 10
123
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123 is 7b

input variant b)

Enter a number with base 10
123456789
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123456789 is 75bcd15

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