# hex() function in Python

hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.

Syntax :

```hex(x)
Parameters :
x - an integer number (int object)

Errors and Exceptions :

```TypeError :  Returns TypeError when anything other than
integer type constants are passed as parameters.```

Code #1 : Illustrates use of hex() function.

 `# Python3 program to illustrate ` `# hex() function ` ` `  `print``(``"The hexadecimal form of 23 is"` `                            ``+` `hex``(``23``)) ` `                             `  `print``(``"The hexadecimal form of the "` `      ``"ascii value is 'a' is "` `+` `hex``(``ord``(``'a'``))) ` `       `  `print``(``"The hexadecimal form of 3.9 is "` `                        ``+` `float``.``hex``(``3.9``)) `

Output :

```The hexadecimal form of 23 is0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1```

Code #2: Demontsrate TypeError when floating point values are passed as parameter.

 `# hex() accepts only integer vaues as parameters ` `print``(``"The hexadecimal form of 11.1 is "` `                            ``+` `hex``(``11.1``)) ` ` `  `''' ` `# The hexadecimal conversion of floating   ` `# point integers can be done using the ` `# function float.hex() ` `print("The hexadecimal form of 11.1 is "  ` `                    ``+ float.hex(11.1)) ` `# Output : ` `# The hexadecimal form of 11.1 is 0x1.6333333333333p+3 ` ` `  `# Similarly, float.hex() throws a TypeError ` `# when integer values are passed in it.  ` `'''`

Output :

```Traceback (most recent call last):
File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in
print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer
```

Applications :
hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.

Code #3 :

 `# TypeConversion from decimal with base 10  ` `# to hexadecimal form with base 16 ` ` `  ` `  `# Taking input from user  ` `# an integer with base 10 ` `number ``=` `int``(``input``(``"Enter a number with base 10\n"``)) ` ` `  `# The choices present to the user ` `print``(``"a. Decimal to Hexadecimal "``) ` `print``(``"b. Decimal to Octal"``) ` `print``(``"c. Decimal to Binary"``) ` ` `  `# taking user input ` `print``(``"Enter your choice :- "``) ` `choice ``=` `input``() ` ` `  `# Running a variable choice ` `# Hexadecimal form if choice ` `# is set to 'a' ` `if` `choice ``is` `'a'``: ` ` `  `    ``# lstrip helps remove "0x" from the left  ` `    ``# rstrip helps remove "L" from the right, ` `    ``# L represents a long number ` `    ``print``(``"Hexadecimal form of "` `+` `str``(number) ``+`  `        ``" is "` `+` `hex``(number).lstrip(``"0x"``).rstrip(``"L"``)) ` `         `  `if` `choice ``is` `'b'``: ` `     `  `    ``# Octal representation is done ` `    ``# by adding a prefix "0o"  ` `    ``print``(``"Octal form of "` `+` `str``(number) ``+` `        ``" is "` `+` `oct``(number).lstrip(``"0o"``).rstrip(``"L"``)) ` `         `  `if` `choice ``is` `'c'``: ` `     `  `    ``# Binary representation is done by ` `    ``# the addition of prefix "0b" ` `    ``print``(``"Binary form of "` `+` `str``(number) ``+`  `        ``" is "``+``bin``(number).lstrip(``"0b"``).rstrip(``"L"``)) `

Output :

```Enter a number with base 10
123
b. Decimal to Octal
c. Decimal to Binary
a
Hexadecimal form of 123 is 7b
```
```Enter a number with base 10
123456789
b. Decimal to Octal
c. Decimal to Binary
a
Hexadecimal form of 123456789 is 75bcd15```

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