Program to find the Perimeter of a Regular Polygon
Last Updated :
21 Aug, 2022
Given the number of sides ‘n’ and the length of side ‘s’ of a regular polygon, the task is to find out the Perimeter of this polygon.
Examples:
Input: n = 7, s = 10
Output: Perimeter : 70
Since the sides are 7,
Hence the given polygon is Heptagon.
Therefore. Perimeter = 7*10 = 70
Input: n = 5, s = 2.5
Output: Perimeter : 12.5
Since the sides are 5,
Hence the given polygon is Pentagon.
Therefore. Perimeter = 5*2.5 = 12.5
Approach: In geometry, a regular polygon is a closed figure with all sides equal. It is a two-dimensional figure.
Perimeter of a Regular Polygon = Number of sides * Length of each side
Below is the implementation of the above approach:
C++
#include <iostream>
using namespace std;
float Perimeter( float s, int n)
{
float perimeter = 1;
perimeter = n * s;
return perimeter;
}
int main()
{
int n = 5;
float s = 2.5, peri;
peri = Perimeter(s, n);
cout << "Perimeter of Regular Polygon"
<< " with " << n << " sides of length "
<< s << " = " << peri << endl;
return 0;
}
|
C
#include <stdio.h>
float Perimeter( float s, int n)
{
float perimeter = 1;
perimeter = n * s;
return perimeter;
}
int main()
{
int n = 5;
float s = 2.5, peri;
peri = Perimeter(s, n);
printf ( "Perimeter of Regular Polygon\n"
" with %d sides of length %f = %f\n" ,
n, s, peri);
return 0;
}
|
Java
class GFG {
static double Perimeter( double s, int n)
{
double perimeter = 1 ;
perimeter = n * s;
return perimeter;
}
public static void main(String[] args)
{
int n = 5 ;
double s = 2.5 , peri;
peri = Perimeter(s, n);
System.out.println( "Perimeter of Regular Polygon"
+ " with " + n + " sides of length "
+ s + " = " + peri);
}
}
|
Python3
def Perimeter(s, n):
perimeter = 1
perimeter = n * s
return perimeter
if __name__ = = '__main__' :
n = 5
s = 2.5
peri = Perimeter(s, n)
print ( "Perimeter of Regular Polygon with"
,n, "sides of length" ,s, "=" ,peri)
|
C#
using System;
class GFG
{
static double Perimeter( double s, int n)
{
double perimeter = 1;
perimeter = n * s;
return perimeter;
}
static public void Main ()
{
int n = 5;
double s = 2.5, peri;
peri = Perimeter(s, n);
Console.WriteLine( "Perimeter of Regular Polygon" +
" with " + n + " sides of length " +
s + " = " + peri);
}
}
|
PHP
<?php
function Perimeter( $s , $n )
{
$perimeter = 1;
$perimeter = $n * $s ;
return $perimeter ;
}
$n = 5;
$s = 2.5;
$peri = Perimeter( $s , $n );
echo "Perimeter of Regular Polygon"
, " with " , $n , " sides of length "
, $s , " = " , $peri ;
?>
|
Javascript
<script>
function Perimeter(s, n)
{
var perimeter = 1;
perimeter = n * s;
return perimeter;
}
var n = 5;
var s = 2.5, peri;
peri = Perimeter(s, n);
document.write( "Perimeter of Regular Polygon<br/>" +
" with " + n + " sides of length " +
s.toFixed(6) + " = " + peri.toFixed(6));
</script>
|
Output:
Perimeter of Regular Polygon
with 5 sides of length 2.500000 = 12.500000
Time Complexity: O(1), since there is no loop or recursion.
Auxiliary Space: O(1), since no extra space has been taken.
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