Program to find the perimeter of a square given its area

Write a program to find the perimeter of a square given its area.

Examples:

Input: Area = 36 square units
Output: Perimeter = 24 units
Explanation: Since the area of the square is 36 square units, so the side of square will be 6 units. Therefore, the perimeter of the square will be 4 * 6 = 24 units.

Input: Area = 25 square units
Output: Perimeter = 20 units
Explanation: Since the area of the square is 25 square units, so the side of square will be 5 units. Therefore, the perimeter of the square will be 4 * 5 = 20 units.

Approach: To solve the problem, follow the below idea:

The area of a square is given by Area=side×side. We can find the side length by taking the square root of the area. Once the side length is known, the perimeter can be calculated as Perimeter=4×side.

Step-by-step algorithm:

• Calculate the side length using the square root of the area.
• Calculate the perimeter using the formula Perimeter=4 × side.
• Print the calculated perimeter.

Below is the implementation of the algorithm:

C++

#include <cmath>
#include <iostream>

using namespace std;

int main()
{
    double area, side, perimeter;

    // Example Test Case
    area = 16;

    // Calculate side length
    side = sqrt(area);

    // Calculate perimeter
    perimeter = 4 * side;

    // Display result
    cout << "Perimeter: " << perimeter << endl;

    return 0;
}

C

#include <math.h>
#include <stdio.h>

int main()
{
    double area, side, perimeter;

    // Example Test Case
    area = 16;

    // Calculate side length
    side = sqrt(area);

    // Calculate perimeter
    perimeter = 4 * side;

    // Display result
    printf("Perimeter: %.2f\n", perimeter);

    return 0;
}

Java

import java.util.Scanner;

public class SquarePerimeter {
    public static void main(String[] args)
    {
        Scanner scanner = new Scanner(System.in);
        double area, side, perimeter;

        // Example Test Case
        area = 16;

        // Calculate side length
        side = Math.sqrt(area);

        // Calculate perimeter
        perimeter = 4 * side;

        // Display result
        System.out.println("Perimeter: " + perimeter);
    }
}

Python3

import math

# Example Test Case
area = 16

# Calculate side length
side = math.sqrt(area)

# Calculate perimeter
perimeter = 4 * side

# Display result
print(f"Perimeter: {perimeter}")

C#

using System;

class Program {
    static void Main()
    {
        double area, side, perimeter;

        // Example Test Case
        area = 16;

        // Calculate side length
        side = Math.Sqrt(area);

        // Calculate perimeter
        perimeter = 4 * side;

        // Display result
        Console.WriteLine("Perimeter: " + perimeter);
    }
}

Javascript

// Example Test Case
let area = 16;

// Calculate side length
let side = Math.sqrt(area);

// Calculate perimeter
let perimeter = 4 * side;

// Display result
console.log(`Perimeter: ${perimeter}`);

Output

Perimeter: 16

Time Complexity: O(log N), because it takes O(logN) time to calculate the square root of N.
Auxiliary Space: O(1)