Given four numbers x, y, z, n. The task is to find the number of solutions for the equation x + y + z <= n, such that 0 <= x <= X, 0 <= y <= Y, 0 <= z <= Z.
Input: x = 1, y = 1, z = 1, n = 1 Output: 4 Input: x = 1, y = 2, z = 3, n = 4 Output: 20
Approach: Let’s iterate explicitly over all possible values of x and y (using nested loop). For one such fixed values of x and y, the problem reduces to how many values of z are there such that z <= n – x – y and 0 <= z <= Z.
Below is the required implementation to find the number of solutions:
- Find the number of solutions to the given equation
- Number of integral solutions of the equation x1 + x2 +.... + xN = k
- Number of integral solutions for equation x = b*(sumofdigits(x)^a)+c
- Number of non-negative integral solutions of sum equation
- Program to find number of solutions in Quadratic Equation
- Find number of solutions of a linear equation of n variables
- Python | Finding Solutions of a Polynomial Equation
- Number of solutions for x < y, where a <= x <= b and c <= y <= d and x, y are integers
- Number of solutions of n = x + n ⊕ x
- Number of non-negative integral solutions of a + b + c = n
- Count number of solutions of x^2 = 1 (mod p) in given range
- Number of solutions to Modular Equations
- Find 'N' number of solutions with the given inequality equations
- Number of sextuplets (or six values) that satisfy an equation
- 0/1 Knapsack Problem to print all possible solutions
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