Program to find number of solutions in Quadratic Equation

Given an equation $ax^{2}\pm bx\pm c=0$ with value a, b, and c, where a and b is any value and c is constant, find how many solutions thus this quadratic equation have?

Examples:

Input : 
Output : 2 solutions

Input : 
Output : no solution

Solution:
To check whether the equation has a solution or not, quadratic formula for discriminant is used.

The formula is given as, $b^{2}-4ac$

Respective conditions are given as,

if the discriminant is positive $b^{2}-4ac> 0$ , then the quadratic equation has two solutions.
if the discriminant is equal $b^{2}-4ac= 0$ , then the quadratic equation has one solution.
if the discriminant is negative $b^{2}-4ac< 0$ , then the quadratic equation has no solution.

Programs:

C++

// C++ Program to find the solutions of specified equations 
#include <iostream> 
using namespace std; 
  
// Method to check for solutions of equations 
void checkSolution(int a, int b, int c) 
{ 
  
    // If the expression is greater than 0, then 2 solutions 
    if (((b * b) - (4 * a * c)) > 0) 
        cout << "2 solutions"; 
  
    // If the expression is equal 0, then 2 solutions 
    else if (((b * b) - (4 * a * c)) == 0) 
        cout << "1 solution"; 
  
    // Else no solutions 
    else
        cout << "No solutions"; 
} 
  
int main() 
{ 
    int a = 2, b = 5, c = 2; 
    checkSolution(a, b, c); 
    return 0; 
} 

Java

// Java Program to find the solutions of specified equations 
public class GFG { 
  
    // Method to check for solutions of equations 
    static void checkSolution(int a, int b, int c) 
    { 
  
        // If the expression is greater than 0,  
        // then 2 solutions 
        if (((b * b) - (4 * a * c)) > 0) 
            System.out.println("2 solutions"); 
  
        // If the expression is equal 0, then 2 solutions 
        else if (((b * b) - (4 * a * c)) == 0) 
            System.out.println("1 solution"); 
  
        // Else no solutions 
        else
            System.out.println("No solutions"); 
    } 
  
    // Driver Code 
    public static void main(String[] args) 
    { 
        int a = 2, b = 5, c = 2; 
        checkSolution(a, b, c); 
    } 
} 

Python 3

# Python3 Program to find the  
# solutions of specified equations  
  
# function to check for 
# solutions of equations  
def checkSolution(a, b, c) : 
  
    # If the expression is greater 
    # than 0, then 2 solutions  
    if ((b * b) - (4 * a * c)) > 0 : 
        print("2 solutions") 
  
    # If the expression is equal 0,  
    # then 1 solutions 
    elif ((b * b) - (4 * a * c)) == 0 : 
        print("1 solution") 
  
    # Else no solutions  
    else : 
        print("No solutions") 
  
# Driver code 
if __name__ == "__main__" : 
  
    a, b, c = 2, 5, 2
    checkSolution(a, b, c) 
  
# This code is contributed 
# by ANKITRAI1 

C#

// C# Program to find the solutions  
// of specified equations 
using System; 
class GFG  
{ 
  
// Method to check for solutions of equations 
static void checkSolution(int a, int b, int c) 
{ 
  
    // If the expression is greater  
    // than 0, then 2 solutions 
    if (((b * b) - (4 * a * c)) > 0) 
        Console.WriteLine("2 solutions"); 
  
    // If the expression is equal to 0, 
    // then 2 solutions 
    else if (((b * b) - (4 * a * c)) == 0) 
        Console.WriteLine("1 solution"); 
  
    // Else no solutions 
    else
        Console.WriteLine("No solutions"); 
} 
  
// Driver Code 
public static void Main() 
{ 
    int a = 2, b = 5, c = 2; 
    checkSolution(a, b, c); 
} 
} 
  
// This code is contributed by inder_verma 

PHP

<?php 
// Program to find the solutions  
// of specified equations 
  
// Method to check for solutions  
// of equations 
function checkSolution($a, $b, $c) 
{ 
  
    // If the expression is greater  
    // than 0, then 2 solutions 
    if ((($b * $b) - (4 * $a * $c)) > 0) 
        echo "2 solutions"; 
  
    // If the expression is equal 0,  
    // then 2 solutions 
    else if ((($b * $b) -  
              (4 * $a * $c)) == 0) 
        echo "1 solution"; 
  
    // Else no solutions 
    else
        echo"No solutions"; 
} 
  
// Driver Code 
$a = 2; $b = 5; $c = 2; 
checkSolution($a, $b, $c); 
  
// This code is contributed  
// by inder_verma 
?> 

Output:

2 solutions

My Personal Notes

C++

Java

Python 3

C#

PHP

Recommended Posts: