Program to find number of solutions in Quadratic Equation

Given an equation ax^{2}\pm bx\pm c=0 with value a, b, and c, where a and b is any value and c is constant, find how many solutions thus this quadratic equation have?

Examples:

Input : 2x^{2}+5x+2=0
Output : 2 solutions

Input : x^{2}+x+1=0
Output : no solution

Solution:
To check whether the equation has a solution or not, quadratic formula for discriminant is used.

The formula is given as, b^{2}-4ac

Respective conditions are given as,

  • if the discriminant is positive b^{2}-4ac> 0, then the quadratic equation has two solutions.
  • if the discriminant is equal b^{2}-4ac= 0, then the quadratic equation has one solution.
  • if the discriminant is negative b^{2}-4ac< 0, then the quadratic equation has no solution.

Programs:

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ Program to find the solutions of specified equations
#include <iostream>
using namespace std;
  
// Method to check for solutions of equations
void checkSolution(int a, int b, int c)
{
  
    // If the expression is greater than 0, then 2 solutions
    if (((b * b) - (4 * a * c)) > 0)
        cout << "2 solutions";
  
    // If the expression is equal 0, then 2 solutions
    else if (((b * b) - (4 * a * c)) == 0)
        cout << "1 solution";
  
    // Else no solutions
    else
        cout << "No solutions";
}
  
int main()
{
    int a = 2, b = 5, c = 2;
    checkSolution(a, b, c);
    return 0;
}

chevron_right






                        filter_none









Java














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// Java Program to find the solutions of specified equations 


public class GFG { 


  


    // Method to check for solutions of equations 


    static void checkSolution(int a, int b, int c) 


    { 


  


        // If the expression is greater than 0,  


        // then 2 solutions 


        if (((b * b) - (4 * a * c)) > 0) 


            System.out.println("2 solutions"); 


  


        // If the expression is equal 0, then 2 solutions 


        else if (((b * b) - (4 * a * c)) == 0) 


            System.out.println("1 solution"); 


  


        // Else no solutions 


        else


            System.out.println("No solutions"); 


    } 


  


    // Driver Code 


    public static void main(String[] args) 


    { 


        int a = 2, b = 5, c = 2; 


        checkSolution(a, b, c); 


    } 


} 



















                        chevron_right







                        filter_none









Python 3














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















# Python3 Program to find the  


# solutions of specified equations  


  


# function to check for 


# solutions of equations  


def checkSolution(a, b, c) : 


  


    # If the expression is greater 


    # than 0, then 2 solutions  


    if ((b * b) - (4 * a * c)) > 0 : 


        print("2 solutions") 


  


    # If the expression is equal 0,  


    # then 1 solutions 


    elif ((b * b) - (4 * a * c)) == 0 : 


        print("1 solution") 


  


    # Else no solutions  


    else : 


        print("No solutions") 


  


# Driver code 


if __name__ == "__main__" : 


  


    a, b, c = 2, 5, 2


    checkSolution(a, b, c) 


  


# This code is contributed 


# by ANKITRAI1 



















                        chevron_right







                        filter_none









C#














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// C# Program to find the solutions  


// of specified equations 


using System; 


class GFG  


{ 


  


// Method to check for solutions of equations 


static void checkSolution(int a, int b, int c) 


{ 


  


    // If the expression is greater  


    // than 0, then 2 solutions 


    if (((b * b) - (4 * a * c)) > 0) 


        Console.WriteLine("2 solutions"); 


  


    // If the expression is equal to 0, 


    // then 2 solutions 


    else if (((b * b) - (4 * a * c)) == 0) 


        Console.WriteLine("1 solution"); 


  


    // Else no solutions 


    else


        Console.WriteLine("No solutions"); 


} 


  


// Driver Code 


public static void Main() 


{ 


    int a = 2, b = 5, c = 2; 


    checkSolution(a, b, c); 


} 


} 


  


// This code is contributed by inder_verma 



















                        chevron_right







                        filter_none









PHP














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















<?php 


// Program to find the solutions  


// of specified equations 


  


// Method to check for solutions  


// of equations 


function checkSolution($a, $b, $c) 


{ 


  


    // If the expression is greater  


    // than 0, then 2 solutions 


    if ((($b * $b) - (4 * $a * $c)) > 0) 


        echo "2 solutions"; 


  


    // If the expression is equal 0,  


    // then 2 solutions 


    else if ((($b * $b) -  


              (4 * $a * $c)) == 0) 


        echo "1 solution"; 


  


    // Else no solutions 


    else


        echo"No solutions"; 


} 


  


// Driver Code 


$a = 2; $b = 5; $c = 2; 


checkSolution($a, $b, $c); 


  


// This code is contributed  


// by inder_verma 


?> 



















                        chevron_right







                        filter_none










Output:


2 solutions



          
          
          
          

            

    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts:
bilal-hungund
सर्वशक्तिशाली इकलौता
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on  the "Improve Article" button below.


Improved By :  inderDuMCA, AnkitRai01