Program to find number of solutions in Quadratic Equation

Given an equation ax^{2}\pm bx\pm c=0 with value a, b, and c, where a and b is any value and c is constant, find how many solutions thus this quadratic equation have?

Examples:

Input : 2x^{2}+5x+2=0
Output : 2 solutions

Input : x^{2}+x+1=0
Output : no solution

Solution:
To check whether the equation has a solution or not, quadratic formula for discriminant is used.



The formula is given as, b^{2}-4ac

Respective conditions are given as,

  • if the discriminant is positive b^{2}-4ac> 0, then the quadratic equation has two solutions.
  • if the discriminant is equal b^{2}-4ac= 0, then the quadratic equation has one solution.
  • if the discriminant is negative b^{2}-4ac< 0, then the quadratic equation has no solution.

Programs:

C++

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// C++ Program to find the solutions of specified equations
#include <iostream>
using namespace std;
  
// Method to check for solutions of equations
void checkSolution(int a, int b, int c)
{
  
    // If the expression is greater than 0, then 2 solutions
    if (((b * b) - (4 * a * c)) > 0)
        cout << "2 solutions";
  
    // If the expression is equal 0, then 2 solutions
    else if (((b * b) - (4 * a * c)) == 0)
        cout << "1 solution";
  
    // Else no solutions
    else
        cout << "No solutions";
}
  
int main()
{
    int a = 2, b = 5, c = 2;
    checkSolution(a, b, c);
    return 0;
}

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Java














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// Java Program to find the solutions of specified equations 


public class GFG { 


  


    // Method to check for solutions of equations 


    static void checkSolution(int a, int b, int c) 


    { 


  


        // If the expression is greater than 0,  


        // then 2 solutions 


        if (((b * b) - (4 * a * c)) > 0) 


            System.out.println("2 solutions"); 


  


        // If the expression is equal 0, then 2 solutions 


        else if (((b * b) - (4 * a * c)) == 0) 


            System.out.println("1 solution"); 


  


        // Else no solutions 


        else


            System.out.println("No solutions"); 


    } 


  


    // Driver Code 


    public static void main(String[] args) 


    { 


        int a = 2, b = 5, c = 2; 


        checkSolution(a, b, c); 


    } 


} 



















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Python 3














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# Python3 Program to find the  


# solutions of specified equations  


  


# function to check for 


# solutions of equations  


def checkSolution(a, b, c) : 


  


    # If the expression is greater 


    # than 0, then 2 solutions  


    if ((b * b) - (4 * a * c)) > 0 : 


        print("2 solutions") 


  


    # If the expression is equal 0,  


    # then 1 solutions 


    elif ((b * b) - (4 * a * c)) == 0 : 


        print("1 solution") 


  


    # Else no solutions  


    else : 


        print("No solutions") 


  


# Driver code 


if __name__ == "__main__" : 


  


    a, b, c = 2, 5, 2


    checkSolution(a, b, c) 


  


# This code is contributed 


# by ANKITRAI1 



















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C#














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// C# Program to find the solutions  


// of specified equations 


using System; 


class GFG  


{ 


  


// Method to check for solutions of equations 


static void checkSolution(int a, int b, int c) 


{ 


  


    // If the expression is greater  


    // than 0, then 2 solutions 


    if (((b * b) - (4 * a * c)) > 0) 


        Console.WriteLine("2 solutions"); 


  


    // If the expression is equal to 0, 


    // then 2 solutions 


    else if (((b * b) - (4 * a * c)) == 0) 


        Console.WriteLine("1 solution"); 


  


    // Else no solutions 


    else


        Console.WriteLine("No solutions"); 


} 


  


// Driver Code 


public static void Main() 


{ 


    int a = 2, b = 5, c = 2; 


    checkSolution(a, b, c); 


} 


} 


  


// This code is contributed by inder_verma 



















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PHP














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<?php 


// Program to find the solutions  


// of specified equations 


  


// Method to check for solutions  


// of equations 


function checkSolution($a, $b, $c) 


{ 


  


    // If the expression is greater  


    // than 0, then 2 solutions 


    if ((($b * $b) - (4 * $a * $c)) > 0) 


        echo "2 solutions"; 


  


    // If the expression is equal 0,  


    // then 2 solutions 


    else if ((($b * $b) -  


              (4 * $a * $c)) == 0) 


        echo "1 solution"; 


  


    // Else no solutions 


    else


        echo"No solutions"; 


} 


  


// Driver Code 


$a = 2; $b = 5; $c = 2; 


checkSolution($a, $b, $c); 


  


// This code is contributed  


// by inder_verma 


?> 



















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Output:


2 solutions



          
          
          
          

            

    

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