Python | Finding Solutions of a Polynomial Equation
Last Updated :
10 Jun, 2021
Given a quadratic equation, the task is to find the possible solutions to it.
Examples:
Input :
enter the coef of x2 : 1
enter the coef of x : 2
enter the constant : 1
Output :
the value for x is -1.0
Input :
enter the coef of x2 : 2
enter the coef of x : 3
enter the constant : 2
Output :
x1 = -3+5.656854249492381i/4 and x2 = -3-5.656854249492381i/4
Algorithm :
Start.
Prompt the values for a, b, c.
Compute i = b**2-4*a*c
If i get negative value g=square root(-i)
Else h = sqrt(i)
Compute e = -b+h/(2*a)
Compute f = -b-h/(2*a)
If condition e==f then
Print e
Else
Print e and f
If i is negative then
Print -b+g/(2*a) and -b-g/(2*a)
stop
Below is the Python implementation of the above mentioned task.
Python3
from math import sqrt
try :
a = 1
b = 2
c = 1
i = b * * 2 - 4 * a * c
g = sqrt( - i)
try :
d = sqrt(i)
e = ( - b + d) / 2 * a
f = ( - b - d) / 2 * a
if e = = f:
print ( "the values for x is " + str (e))
else :
print ( "the value for x1 is " + str (e) +
" and x2 is " + str (f))
except ValueError:
print ( "the result for your equation is in complex" )
print ( "x1 = " + str ( - b) + "+" + str (g) + "i/" + str ( 2 * a) +
" and x2 = " + str ( - b) + "-" + str (g) + "i/" +
str ( 2 * a))
except ValueError:
print ( "enter a number not a string or char" )
|
Output :
the values for x is -1.0
Explanation :
First, this program will get three inputs from the user. The values are the coefficient of , coefficient of and constant. Then it performs the formula
For complex the value of gets negative. Rooting negative values will throw a value error. In this case, turn the result of and then root it. Don’t forget to include at last.
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