Given three integers A, B and C, the task is to find the count of values of X such that the following condition is satisfied,
X = B * Sm(X)A + C where Sm(X) denotes the sum of digits of X and 1 < X < 109.
Input: A = 3, B = 2, C = 8
For X = 10, 2 * (1)3 + 8 = 10
For X = 2008, 2 * (10)3 + 8 = 2008
For X = 13726, 2 * (19)3 + 8 = 13726
Input: A = 2, B = 3, C = 10
Approach: An important observation can be made here that the sum of digits can be atmost 81 (i.e. X = 999999999) and corresponding to each sum of digits, we get a single value of X. So we can iterate through each sum of digit and check if the resulting value of X is valid or not.
Below is the implementation of the above approach:
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