MySQL | PARTITION BY Clause

A PARTITION BY clause is used to partition rows of table into groups. It is useful when we have to perform a calculation on individual rows of a group using other rows of that group.

• It is always used inside OVER() clause.
• The partition formed by partition clause are also known as Window.
• This clause works on windows functions only. Like- RANK(), LEAD(), LAG() etc.
• If this clause is omitted in OVER() clause, then whole table is considered as a single partition.

Syntax:
The syntax for Partition clause is-

Window_function ( expression ) 
       Over ( partition by expr [order_clause] [frame_clause] ) 

Here, order_clause and frame_clause are optional.

expr can be column names or built-in functions in MySQL.

But, standard SQL permits only column names in expr.

Examples:

Consider, a table “Hacker“:

h_id	h_name	challenge_id	score
3	shubh	111	20
2	aayush	111	80
5	krithik	112	40
5	krithik	114	90
4	tushar	112	30
1	parth	112	40

We have to find the rank of hackers in each challenge. That means we have to list all participated hackers of a challenge along with their rank in that challenge.

Query:

select challenge_id, h_id, h_name, score, 
   dense_rank() over ( partition by challenge_id order by score desc ) 
       as "rank", from hacker;

Explanation:

In the above query, partition by clause will partition table into groups that are having same challenge_id.

order by will arrange the hackers of each partition in descending order by “scores”.

over() clause defines how to partition and order rows of table, which is to be processed by window function rank().

dense_rank() is a window function, which will assign rank in ordered partition of challenges. If two hackers have same scores then they will be assigned same rank.

Output:

challenge_id	h_id	h_name	score	rank
111	2	aayush	80	1
111	3	shubh	20	2
112	5	krithik	40	1
112	1	parth	40	1
112	4	tushar	30	2
114	5	krithik	90	1

Thus, we get list of all hackers along with their ranks in the individual challenges.

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