Javascript Program for Check whether all the rotations of a given number is greater than or equal to the given number or not
Given an integer x, the task is to find if every k-cycle shift on the element produces a number greater than or equal to the same element.
A k-cyclic shift of an integer x is a function that removes the last k digits of x and inserts them in its beginning.
For example, the k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2. Print Yes if the given condition is satisfied else print No.
Examples:
Input: x = 123
Output : Yes
The k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2.
Both 312 and 231 are greater than 123.
Input: 2214
Output: No
The k-cyclic shift of 2214 when k=2 is 1422 which is smaller than 2214
Approach: Simply find all the possible k cyclic shifts of the number and check if all are greater than the given number or not.
Below is the implementation of the above approach:
Javascript
<script> // javascript implementation of the approachfunction CheckKCycles(n, s) { var ff = true; var x = 0; for (i = 1; i < n; i++) { // Splitting the number at index i // and adding to the front x = (s.substring(i) + s.substring(0, i)).length; // Checking if the value is greater than // or equal to the given value if (x >= s.length) { continue; } ff = false; break; } if (ff) { document.write("Yes"); } else { document.write("No"); }} // Driver code var n = 3; var s = "123"; CheckKCycles(n, s); // This code is contributed by 29AjayKumar </script> |
Yes
Please refer complete article on Check whether all the rotations of a given number is greater than or equal to the given number or not for more details!
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