How to Convert JSON String to a JSON Object in Scala?

When working with JSON data in Scala, we may often need to convert a JSON string into a JSON object. This can be useful for parsing and manipulating JSON data effectively. This article focuses on discussing ways to convert JSON string to a JSON object.

Using the Built-in Parse Method

This approach leverages the parse() the method provided by the JSON library in Scala.

Syntax:

val jsonObject = Json.parse(jsonString)

The parse method parses the JSON string and returns a JSON object.

Below is the Scala program to convert a JSON string to a JSON object using the built-in parse method:

Scala

import play.api.libs.json.Json;

val jsonString = "{\"name\": \"John\", \"age\": 30}";
val jsonObject = Json.parse(jsonString);
println(jsonObject)

Output:

Using the Built-in Parse Method

Using the Read Method

This approach utilizes the read method from the Json library to read the JSON string and convert it into a JSON object.

Syntax:

val jsonObject = Json.parse(jsonString).as[JsValue]

The as method with [JsValue] type conversion is used to convert the parsed JSON string into a JSON object.

Below is the Scala program to convert a JSON string to JSON object using the read method:

Scala

import play.api.libs.json.{Json, JsValue}

val jsonString = "{\"name\": \"John\", \"age\": 30}"
val jsonObject = Json.parse(jsonString).as[JsValue]
println(jsonObject)

Output:

Using the Read Method

Using the Jackson Library

This approach involves using the Jackson library for JSON processing in Scala. The readTree method from the ObjectMapper class is used to parse the JSON string and create a JSON object.

Below is the Scala program to convert a JSON string to JSON object using the jackson library method:

Scala

import com.fasterxml.jackson.databind.ObjectMapper

val jsonString = "{\"name\": \"John\", \"age\": 30}"
val mapper = new ObjectMapper()
val jsonObject = mapper.readTree(jsonString)
println(jsonObject)

Output:

Using the Jackson Library

Using the Circe Library

This approach utilizes the Circe library, which is a JSON library for Scala.

Syntax:

parse(jsonString)

Return Type:

JSON

The parse function from the Circe library is used to parse the JSON string and convert it into a JSON object.

Dependency:

Add the following to your sbt configuration

val circeVersion = “0.14.3” libraryDependencies ++= Seq( “io.circe” %% “circe-core”, “io.circe” %% “circe-generic”, “io.circe” %% “circe-parser” ).map(_ % circeVersion)

Below is the Scala program to convert a JSON string to JSON object using the circle library:

Swift

import io.circe.parser._

val jsonString = "{\"name\": \"John\", \"age\": 30}"
val jsonObject = parse(jsonString)
println(jsonObject)

Output:

Using the Circe Library

Conclusion

Converting JSON strings to JSON objects in Scala is a common task when dealing with JSON data. By using the methods provided by libraries like Json, Jackson, and Circe, developers can efficiently parse JSON strings and work with JSON objects in their Scala applications.