# Highest power of two that divides a given number

Given a number n, find the highest power of 2 that divides n.

**Examples:**

Input : n = 48

Output : 16

Highest power of 2 that divides 48 is 16.Input : n = 5

Output : 1

Highest power of 2 that divides 5 is 1.

A **simple solution **is to try all powers of 2 one by one starting from 1, then 2, then 4 and so on.

An **efficient solution** is based on bit magic. If we take a closer look, we can notice that, we basically need to find the number that has rightmost bit set at same position as n and all other bits as 0. For example, for n = 5 (10**1**), our output is 00**1**. For n = 48 (1**1**0000), our output is 0**1**0000

*How do we find a number that has same rightmost set bit and all other bits as 0?*

We follow below steps.

Let n = 48 (00110000)

Subtract one from n, i.e., we do **n-1**. We get 47(00101111)

Do negation of (n-1), i.e., we do **~(n-1)**. We get (11010000).

Do n & **(~(n-1))**, we get 00010000 which has value 16.

Below is the implementation of above approach:

## C++

`// CPP program to find highest power ` `// of 2 that divides n. ` `#include<iostream> ` `using` `namespace` `std; ` ` ` `int` `highestPowerOf2(` `int` `n) ` `{ ` ` ` `return` `(n & (~(n - 1))); ` `} ` ` ` `int` `main() ` `{ ` ` ` `int` `n = 48; ` ` ` `cout << highestPowerOf2(n); ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

## Java

`// Java program to find highest power ` `// of 2 that divides n. ` ` ` `class` `GFG ` `{ ` ` ` `static` `int` `highestPowerOf2(` `int` `n) ` `{ ` ` ` `return` `(n & (~(n - ` `1` `))); ` `} ` ` ` `public` `static` `void` `main(String []args) ` `{ ` ` ` `int` `n = ` `48` `; ` ` ` `System.out.println(highestPowerOf2(n)); ` `} ` `} ` ` ` |

*chevron_right*

*filter_none*

## Python3

`# Python3 program to find highest power ` `# of 2 that divides n. ` ` ` `def` `highestPowerOf2(n): ` ` ` ` ` `return` `(n & (~(n ` `-` `1` `))) ` ` ` ` ` `#Driver code ` `if` `__name__` `=` `=` `'__main__'` `: ` ` ` `n ` `=` `48` ` ` `print` `(highestPowerOf2(n)) ` ` ` `# this code is contributed ` `# by ash264 ` |

*chevron_right*

*filter_none*

## C#

`// C# program to find highest power ` `// of 2 that divides n. ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` `static` `int` `highestPowerOf2(` `int` `n) ` `{ ` ` ` `return` `(n & (~(n - 1))); ` `} ` ` ` `public` `static` `void` `Main() ` `{ ` ` ` `int` `n = 48; ` ` ` `Console.Write(highestPowerOf2(n)); ` `} ` `} ` ` ` `// This code is contributed ` `// by Akanksha Rai(Abby_akku) ` |

*chevron_right*

*filter_none*

## PHP

`<?php ` `// PHP program to find highest power ` `// of 2 that divides n. ` ` ` `function` `highestPowerOf2(` `$n` `) ` `{ ` ` ` `return` `(` `$n` `& (~(` `$n` `- 1))); ` `} ` ` ` `// Driver Code ` `$n` `= 48; ` `echo` `highestPowerOf2(` `$n` `); ` ` ` `// This code is contributed ` `// by Sach_Code.. ` `?> ` |

*chevron_right*

*filter_none*

**Output:**

16

## Recommended Posts:

- Highest power of 2 that divides a number represented in binary
- Highest power of 2 less than or equal to given number
- Check if given number is a power of d where d is a power of 2
- Minimum value that divides one number and divisible by other
- Check if the sum of digits of a number N divides it
- Largest number that divides x and is co-prime with y
- Check if a M-th fibonacci number divides N-th fibonacci number
- Find whether a given number is a power of 4 or not
- Number of pairs whose sum is a power of 2
- Check if a number is power of 8 or not
- Compute modulus division by a power-of-2-number
- Breaking a number such that first part is integral division of second by a power of 10
- Minimum removals in a number to be divisible by 10 power raised to K
- Smallest integer > 1 which divides every element of the given array
- Find element in array that divides all array elements

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.