Given a number **N **containing digits from **1 to 9** only. The task is to generate a new number using the number N such that the frequency of each digit in the new number is equal to the frequency of that digit in N multiplied by the digit itself.**Note**: The digits in the new number must be in increasing order.**Examples**:

Input: N = 312Output: 122333Explanation: The output contains digit 1 once, digit 2 twice and digit 3 thrice.Input: N = 525Output: 225555555555Explanation: The output contains digit 2 twice and digit 5 ten times. 5 is ten times because its frequency is 2 in the given integer.

The idea is to store the count or the frequency of the digits in the given number N using a counting array or hash. Now, for each digit add it to the new number, K number of times where K is equal to its frequency in the counting array multiplied by the digit itself.

Below is the implementation of the above approach:

## C++

`// CPP program to print a number such that the` `// frequency of each digit in the new number is` `// is equal to its frequency in the given number` `// multiplied by the digit itself.` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to print such a number` `void` `printNumber(` `int` `n)` `{` ` ` `// initializing a hash array` ` ` `int` `count[10] = { 0 };` ` ` `// counting frequency of the digits` ` ` `while` `(n) {` ` ` `count[n % 10]++;` ` ` `n /= 10;` ` ` `}` ` ` `// printing the new number` ` ` `for` `(` `int` `i = 1; i < 10; i++) {` ` ` `for` `(` `int` `j = 0; j < count[i] * i; j++)` ` ` `cout << i;` ` ` `}` `}` `// Driver code` `int` `main()` `{` ` ` `int` `n = 3225;` ` ` `printNumber(n);` ` ` `return` `0;` `}` |

## Java

`// Java program to print a number such that the` `// frequency of each digit in the new number is` `// is equal to its frequency in the given number` `// multiplied by the digit itself.` `import` `java.io.*;` `class` `GFG {` ` ` `// Function to print such a number` `static` `void` `printNumber(` `int` `n)` `{` ` ` `// initializing a hash array` ` ` `int` `count[] = ` `new` `int` `[` `10` `];` ` ` `// counting frequency of the digits` ` ` `while` `(n>` `0` `) {` ` ` `count[n % ` `10` `]++;` ` ` `n /= ` `10` `;` ` ` `}` ` ` `// printing the new number` ` ` `for` `(` `int` `i = ` `1` `; i < ` `10` `; i++) {` ` ` `for` `(` `int` `j = ` `0` `; j < count[i] * i; j++)` ` ` `System.out.print(i);` ` ` `}` `}` `// Driver code` ` ` `public` `static` `void` `main (String[] args) {` ` ` `int` `n = ` `3225` `;` ` ` `printNumber(n);` ` ` `}` `}` `// This code is contributed by inder_verma` |

## Python3

`# Python 3 program to print a number such that the` `# frequency of each digit in the new number is` `# is equal to its frequency in the given number` `# multiplied by the digit itself.` `# Function to print such a number` `def` `printNumber(n):` ` ` `# initializing a hash array` ` ` `count ` `=` `[` `0` `]` `*` `10` ` ` `# counting frequency of the digits` ` ` `while` `(n) :` ` ` `count[n ` `%` `10` `] ` `+` `=` `1` ` ` `n ` `/` `/` `=` `10` ` ` `# printing the new number` ` ` `for` `i ` `in` `range` `(` `1` `,` `10` `) :` ` ` `for` `j ` `in` `range` `(count[i] ` `*` `i):` ` ` `print` `(i,end` `=` `"")` `# Driver code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `n ` `=` `3225` ` ` `printNumber(n)` ` ` `# This code is contributed by` `# ChitraNayal` |

## C#

`// C# program to print a number such` `// that the frequency of each digit` `// in the new number is equal to its` `// frequency in the given number` `// multiplied by the digit itself.` `using` `System;` `class` `GFG` `{` `// Function to print such a number` `static` `void` `printNumber(` `int` `n)` `{` ` ` `// initializing a hash array` ` ` `int` `[]count = ` `new` `int` `[10];` ` ` `// counting frequency of` ` ` `// the digits` ` ` `while` `(n > 0)` ` ` `{` ` ` `count[n % 10]++;` ` ` `n /= 10;` ` ` `}` ` ` `// printing the new number` ` ` `for` `(` `int` `i = 1; i < 10; i++)` ` ` `{` ` ` `for` `(` `int` `j = 0;` ` ` `j < count[i] * i; j++)` ` ` `Console.Write(i);` ` ` `}` `}` `// Driver code` `public` `static` `void` `Main ()` `{` ` ` `int` `n = 3225;` ` ` `printNumber(n);` `}` `}` `// This code is contributed` `// by inder_verma` |

## PHP

`<?php` `// PHP program to print a number such` `// that the frequency of each digit` `// in the new number is equal to its` `// frequency in the given number` `// multiplied by the digit itself.` `// Function to print such a number` `function` `printNumber(` `$n` `)` `{` ` ` `// initializing a hash array` ` ` `$count` `= ` `array` `();` ` ` `for` `(` `$i` `= 0; ` `$i` `<= 10; ` `$i` `++)` ` ` `$count` `[` `$i` `] = 0;` ` ` ` ` `// counting frequency of the digits` ` ` `while` `(` `$n` `)` ` ` `{` ` ` `$count` `[` `$n` `% 10]++;` ` ` `$n` `/= 10;` ` ` `}` ` ` `// printing the new number` ` ` `for` `(` `$i` `= 1; ` `$i` `< 10; ` `$i` `++)` ` ` `{` ` ` `for` `(` `$j` `= 0;` ` ` `$j` `< ` `$count` `[` `$i` `] * ` `$i` `; ` `$j` `++)` ` ` `echo` `$i` `;` ` ` `}` `}` `// Driver code` `$n` `= 3225;` `printNumber(` `$n` `);` `// This code is contributed` `// by Akanksha Rai(Abby_akku)` |

## Javascript

`<script>` `// JavaScript program to print` `// a number such that the` `// frequency of each digit` `// in the new number is` `// is equal to its frequency` `// in the given number` `// multiplied by the digit itself.` `// Function to print such a number` `function` `printNumber(n)` `{` ` ` `// initializing a hash array` ` ` `let count = ` `new` `Uint8Array(10);` ` ` `// counting frequency of the digits` ` ` `while` `(n) {` ` ` `count[n % 10]++;` ` ` `n = Math.floor(n / 10);` ` ` `}` ` ` `// printing the new number` ` ` `for` `(let i = 1; i < 10; i++) {` ` ` `for` `(let j = 0; j < count[i] * i; j++)` ` ` `document.write(i);` ` ` `}` `}` `// Driver code` ` ` `let n = 3225;` ` ` `printNumber(n);` `// This code is contributed by Surbhi Tyagi.` `</script>` |

**Output:**

222233355555

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