A magic number is defined as a number which can be expressed as a power of 5 or sum of unique powers of 5. First few magic numbers are 5, 25, 30(5 + 25), 125, 130(125 + 5), ….
Write a function to find the nth Magic number.
Example:
Input: n = 2 Output: 25 Input: n = 5 Output: 130
If we notice carefully the magic numbers can be represented as 001, 010, 011, 100, 101, 110 etc, where 001 is 0*pow(5,3) + 0*pow(5,2) + 1*pow(5,1). So basically we need to add powers of 5 for each bit set in given integer n.
Below is the implementation based on this idea.
C++
// C++ program to find nth magic numebr #include <bits/stdc++.h> using namespace std; // Function to find nth magic numebr int nthMagicNo( int n) { int pow = 1, answer = 0; // Go through every bit of n while (n) { pow = pow *5; // If last bit of n is set if (n & 1) answer += pow ; // proceed to next bit n >>= 1; // or n = n/2 } return answer; } // Driver program to test above function int main() { int n = 5; cout << "nth magic number is " << nthMagicNo(n) << endl; return 0; } |
Java
// Java program to find nth // magic numebr import java.io.*; class GFG { // Function to find nth magic number static int nthMagicNo( int n) { int pow = 1 , answer = 0 ; // Go through every bit of n while (n != 0 ) { pow = pow* 5 ; // If last bit of n is set if (( int )(n & 1 ) == 1 ) answer += pow; // proceed to next bit // or n = n/2 n >>= 1 ; } return answer; } // Driver program to test // above function public static void main(String[] args) { int n = 5 ; System.out.println( "nth magic" + " number is " + nthMagicNo(n)); } } // This code is contributed by // prerna saini |
Python3
# Python program to find nth magic numebr # Function to find nth magic numebr def nthMagicNo(n): pow = 1 answer = 0 # Go through every bit of n while (n): pow = pow * 5 # If last bit of n is set if (n & 1 ): answer + = pow # proceed to next bit n >> = 1 # or n = n/2 return answer # Driver program to test above function n = 5 print ( "nth magic number is" , nthMagicNo(n)) # This code is contributed by # Smitha Dinesh Semwal |
C#
// C# program to find nth // magic numebr using System; public class GFG { // Function to find nth magic number static int nthMagicNo( int n) { int pow = 1, answer = 0; // Go through every bit of n while (n != 0) { pow = pow * 5; // If last bit of n is set if (( int )(n & 1) == 1) answer += pow; // proceed to next bit // or n = n/2 n >>= 1; } return answer; } // Driver Code public static void Main() { int n = 5; Console.WriteLine( "nth magic" + " number is " + nthMagicNo(n)); } } // This code is contributed by Sam007 |
PHP
<?php // PHP program to find nth // magic number // Function to find nth // magic number function nthMagicNo( $n ) { $pow = 1; $answer = 0; // Go through every bit of n while ( $n ) { $pow = $pow * 5; // If last bit of n is set if ( $n & 1) $answer += $pow ; // proceed to next bit $n >>= 1; // or $n = $n/2 } return $answer ; } // Driver Code $n = 5; echo "nth magic number is " , nthMagicNo( $n ), "\n" ; // This code is contributed by Ajit. ?> |
Output :
nth magic number is 130
Thanks to manrajsingh for suggesting above solution.
This article is contributed by Abhay. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
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