We can traverse the tree starting from the root level and keep curr_level of the node. Increment the curr_level each time we go to left or a right subtree. Return the max depth of an odd level,if it exists.
1) return 0 if curr_node == NULL
2) if curr_node is leaf and curr_level is odd,
3) else maximum(depthOdd(left subtree),
Let us create Binary Tree shown in above example */
Node root = newNode(10);
root.left = newNode(28);
root.right = newNode(13);
root.right.left = newNode(14);
root.right.right = newNode(15);
root.right.right.left = newNode(23);
root.right.right.right = newNode(24);
// This code is contributed by PrinciRaj1992
This article is contributed by Shubham Gupta. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to firstname.lastname@example.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.