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D3.js line() method

  • Last Updated : 19 Aug, 2020

The d3.line() method is used to constructs a new line generator with the default settings. The line generator is then used to make a line.

Syntax:

d3.line();

Parameters: This method takes no parameters.

Return Value: This method returns a line Generator.

Example 1: Making a simple line using this method.






<!DOCTYPE html>
<html>
<meta charset="utf-8">
<head>
  <title>Line in D3.js</title>
</head>
<script src=
</script>
  
<style>
path {
    fill: none;
    stroke: green;
}
</style>
  
<body>
    <h1 style="text-align: center;
        color: green;">GeeksforGeeks</h1>
  <center>
    <svg width="500" height="500">
    <path></path>
  </svg>
</center>
  <script>
        // Making a line Generator
        var Gen = d3.line();
        var points = [
            [0, 100],
            [500, 100]
             
        ];
  
        var pathOfLine = Gen(points);
  
        d3.select('path')
            .attr('d', pathOfLine);
  </script>
</body>
</html>

Output:

Example 2: Making a Multiconnected line.




<!DOCTYPE html>
<html>
<meta charset="utf-8">
<head>
  <title>Line in D3.js</title>
</head>
<script src=
</script>
  
<style>
path {
    fill: none;
    stroke: green;
}
</style>
  
<body>
    <h1 style="text-align: center;
        color: green;">GeeksforGeeks</h1>
  <center>
    <svg width="500" height="500">
    <path></path>
  </svg>
</center>
  <script>
        // Making a line Generator
        var Gen = d3.line();
        var points = [
            [0, 100],
            [500, 100],
            [200, 200],
            [500, 200]
             
        ];
  
        var pathOfLine = Gen(points);
  
        d3.select('path')
            .attr('d', pathOfLine);
  </script>
</body>
</html>

Output:

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