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D3.js style() Function
  • Last Updated : 09 Aug, 2020

The d3.style() function in D3.js is used to style the specified node(attribute) with the specified name(Value). In this, if the node has an inline style with the specified name, its value is returned and if the node has not an inline style, the calculated value is returned.

Syntax: 

d3.style(node, name)

Parameters: This function accepts two parameters as mentioned above and described below:

  • node: This is a property of the selected element.
  • name: This is the value of the specified attribute.

Return Value: This function returns the value style property for the specified node(attribute) with the specified name(Value).

Below examples illustrate the d3.style() function in D3.js
Example 1:



html




<!DOCTYPE html>
<html>
    <head>
        <title>
            D3.js | d3.style() Function
        </title>
  
        <script src=
        </script>
    </head>
  
    <body>
        <p style="color: green;">
          GeeksforGeeks
        </p>
  
        <p style="color: green;">
          A computer science portal for geeks
        </p>
  
        <script>
            
            // Calling the style() function
            d3.select("p").style("color", "red");
        </script>
    </body>
</html>

Output: 
 

Example 2:

html




<!DOCTYPE html>
<html>
    <head>
        <title>
            D3.js | d3.style() Function
        </title>
  
        <script src=
        </script>
    </head>
  
    <body>
        <p style="color: green;">
          GeeksforGeeks
        </p>
  
  
        <p style="color: green;">
          A computer science portal for geeks
        </p>
  
        <script>
            // Calling the style() function
            d3.select("p").style("font-size", "40px");
        </script>
    </body>
</html>

Output: 

full-stack-img

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