C Program for Difference between sums of odd and even digits
Given a long integer, we need to find if the difference between sum of odd digits and sum of even digits is 0 or not. The indexes start from zero (0 index is for leftmost digit).
Examples:
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Input : 1212112 Output : Yes Explanation:- the odd position element is 2+2+1=5 the even position element is 1+1+1+2=5 the difference is 5-5=0.so print yes. Input :12345 Output : No Explanation:- the odd position element is 1+3+5=9 the even position element is 2+4=6 the difference is 9-6=3 not equal to zero. So print no.
Method 1: One by one traverse digits and find the two sums. If difference between two sums is 0, print yes, else no.
Method 2 : This can be easily solved using divisibility of 11. This condition is only satisfied if the number is divisible by 11. So check the number is divisible by 11 or not.
// C++ program to check if difference between sum of// odd digits and sum of even digits is 0 or not#include <bits/stdc++.h>using namespace std; bool isDiff0(long long int n){ return (n % 11 == 0);} int main(){ long int n = 1243; if (isDiff0(n)) cout << "Yes"; else cout << "No"; return 0;} |
Output:
Yes
Please refer complete article on Difference between sums of odd and even digits for more details!
