# Difference between sums of odd and even digits

Given a long integer, we need to find if the difference between sum of odd digits and sum of even digits is 0 or not. The indexes start from zero (0 index is for leftmost digit).

Examples:

Input : 1212112 Output : Yes Explanation:- the odd position element is 2+2+1=5 the even position element is 1+1+1+2=5 the difference is 5-5=0.so print yes. Input :12345 Output : No Explanation:- the odd position element is 1+3+5=9 the even position element is 2+4=6 the difference is 9-6=3 not equal to zero. So print no.

**Method 1: ** One by one traverse digits and find the two sums. If difference between two sums is 0, print yes, else no.

**Method 2 :** This can be easily solved using divisibility of 11. This condition is only satisfied if the number is divisible by 11. So check the number is divisible by 11 or not.

## CPP

`// C++ program to check if difference between sum of ` `// odd digits and sum of even digits is 0 or not ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `bool` `isDiff0(` `long` `long` `int` `n) ` `{ ` ` ` `return` `(n % 11 == 0); ` `} ` ` ` `int` `main() { ` ` ` ` ` `long` `int` `n = 1243 ` ` ` `if` `(isDiff0(n)) ` ` ` `cout << ` `"Yes"` `; ` ` ` `else` ` ` `cout << ` `"No"` `; ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to check if difference between sum of ` `// odd digits and sum of even digits is 0 or not ` ` ` `import` `java.io.*; ` `import` `java.util.*; ` ` ` `class` `GFG ` `{ ` ` ` `public` `static` `boolean` `isDiff(` `int` `n) ` ` ` `{ ` ` ` `return` `(n % ` `11` `== ` `0` `); ` ` ` `} ` ` ` `public` `static` `void` `main (String[] args) ` ` ` `{ ` ` ` `int` `n = ` `1243` `; ` ` ` `if` `(isDiff(n)) ` ` ` `System.out.print(` `"Yes"` `); ` ` ` `else` ` ` `System.out.print(` `"No"` `); ` ` ` `} ` `} ` |

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## Python

`# Python program to check if difference between sum of ` `# odd digits and sum of even digits is 0 or not ` ` ` `def` `isDiff(n): ` ` ` `return` `(n ` `%` `11` `=` `=` `0` `) ` ` ` `# Driver code ` `n ` `=` `1243` `; ` `if` `(isDiff(n)): ` ` ` `print` `(` `"Yes"` `) ` `else` `: ` ` ` `print` `(` `"No"` `) ` ` ` `# Mohit Gupta_OMG <0_o> ` |

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## C#

`// C# program to check if difference ` `// between sum of odd digits and sum ` `// of even digits is 0 or not ` `using` `System; ` ` ` `class` `GFG { ` ` ` ` ` `public` `static` `bool` `isDiff(` `int` `n) ` ` ` `{ ` ` ` `return` `(n % 11 == 0); ` ` ` `} ` ` ` ` ` `public` `static` `void` `Main () ` ` ` `{ ` ` ` `int` `n = 1243; ` ` ` ` ` `if` `(isDiff(n)) ` ` ` `Console.WriteLine(` `"Yes"` `); ` ` ` `else` ` ` `Console.WriteLine(` `"No"` `); ` ` ` `} ` `} ` ` ` `// This code is contributed by vt_m. ` |

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## PHP

`<?php ` `// PHP program to check if ` `// difference between sum of ` `// odd digits and sum of ` `// even digits is 0 or not ` ` ` `function` `isDiff0(` `$n` `) ` `{ ` ` ` `return` `(` `$n` `% 11 == 0); ` `} ` ` ` ` ` `// Driver Code ` ` ` `$n` `= 1243; ` ` ` `if` `(isDiff0(` `$n` `)) ` ` ` `echo` `"Yes"` `; ` ` ` `else` ` ` `echo` `"No"` `; ` ` ` `// This code is contributed by nitin mittal ` `?> ` |

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**Output:**

Yes

This article is contributed by **jaspal singh**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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