Two integers n and k are given. Our task is to print K-rounding of n. K-rounding is the minimum positive integer X, such that x ends with k or more zeros and is divisible by n.

**Examples :**

Input : n = 30, k = 3. Output : 3000 3000 is the smallest number that has at-least k 0s and is divisible by n. Input : n = 375, k = 4. Output : 30000

**Method 1 :**

The brute force approach is to start with result = 10^{k}. Check if result is divided by n. If yes, it’s the answer, else increase it by 10^{k}

**Method 2 :** The efficient approach is to calculate the LCM of 10^{k} and n.

Suppose, n = 375, k = 4.

result = 10000.

Now, LCM of 375 and 10000 is the lowest number divided by both of them.

It will contain k or more zeros (because it is multiple of 10^{k}) and will be a multiple of n as well.

Below is the implementation :

## C++

`// CPP code to print K-rounded value of n ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to compute the rounded value ` `long` `long` `getRounding(` `long` `long` `n, ` `long` `long` `k) ` `{ ` ` ` `long` `long` `rounding = ` `pow` `(10, k); ` ` ` ` ` `// Computing GCD ` ` ` `long` `long` `result = __gcd(rounding, n); ` ` ` ` ` `// Returning LCM (GCD * LCM = n * k) ` ` ` `return` `((rounding * n) / result); ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` ` ` `long` `long` `n = 375, k = 4; ` ` ` ` ` `// Function call ` ` ` `cout << getRounding(n, k); ` ` ` ` ` `return` `0; ` `} ` |

## Java

`// JAVA Code For Smallest number divisible by ` `// n and has at-least k trailing zeros ` `import` `java.util.*; ` ` ` `class` `GFG { ` ` ` ` ` `// Function to find gcd ` ` ` `static` `long` `gcd(` `long` `a, ` `long` `b) ` ` ` `{ ` ` ` `// Everything divides 0 ` ` ` `if` `(a == ` `0` `|| b == ` `0` `) ` ` ` `return` `0` `; ` ` ` ` ` `// base case ` ` ` `if` `(a == b) ` ` ` `return` `a; ` ` ` ` ` `// a is greater ` ` ` `if` `(a > b) ` ` ` `return` `gcd(a-b, b); ` ` ` `return` `gcd(a, b-a); ` ` ` `} ` ` ` ` ` `// Function to compute the rounded value ` ` ` `public` `static` `long` `getRounding(` `long` `n, ` `long` `k) ` ` ` `{ ` ` ` `long` `rounding = (` `long` `)Math.pow(` `10` `, k); ` ` ` ` ` `// Computing GCD ` ` ` `long` `result = gcd(rounding, n); ` ` ` ` ` `// Returning LCM (GCD * LCM = n * k) ` ` ` `return` `((rounding * n) / result); ` ` ` `} ` ` ` ` ` `/* Driver program to test above function */` ` ` `public` `static` `void` `main(String[] args) ` ` ` `{ ` ` ` `long` `n = ` `375` `, k = ` `4` `; ` ` ` ` ` `// Function call ` ` ` `System.out.println( getRounding(n, k)); ` ` ` ` ` `} ` `} ` ` ` `// This code is contributed by Arnav Kr. Mandal. ` |

## Python3

`# python Code For Smallest number ` `# divisible by n and has ` `# at-least k trailing zeros ` ` ` `# Function to find gcd ` `def` `gcd(a, b): ` ` ` ` ` `# Everything divides 0 ` ` ` `if` `(a ` `=` `=` `0` `or` `b ` `=` `=` `0` `): ` ` ` `return` `0` ` ` ` ` `# base case ` ` ` `if` `(a ` `=` `=` `b): ` ` ` `return` `a ` ` ` ` ` `# a is greater ` ` ` `if` `(a > b): ` ` ` `return` `gcd(a ` `-` `b, b) ` ` ` ` ` `return` `gcd(a, b ` `-` `a) ` ` ` `# Function to compute the ` `# rounded value ` `def` `getRounding(n, k): ` ` ` ` ` `rounding ` `=` `pow` `(` `10` `, k); ` ` ` ` ` `# Computing GCD ` ` ` `result ` `=` `gcd(rounding, n) ` ` ` ` ` `# Returning LCM (GCD * LCM ` ` ` `# = n * k) ` ` ` `return` `((rounding ` `*` `n) ` `/` `result) ` ` ` `# Driver Code ` ` ` `n ` `=` `375` `k ` `=` `4` ` ` `# Function call ` `print` `( ` `int` `(getRounding(n, k))) ` ` ` `# This code is contributed by Sam007 ` |

## C#

`// C# Code For Smallest number ` `// divisible by n and has ` `// at-least k trailing zeros ` `using` `System; ` ` ` `class` `GFG { ` ` ` ` ` `// Function to find gcd ` ` ` `static` `long` `gcd(` `long` `a, ` `long` `b) ` ` ` `{ ` ` ` ` ` `// Everything divides 0 ` ` ` `if` `(a == 0 || b == 0) ` ` ` `return` `0; ` ` ` ` ` `// base case ` ` ` `if` `(a == b) ` ` ` `return` `a; ` ` ` ` ` `// a is greater ` ` ` `if` `(a > b) ` ` ` `return` `gcd(a - b, b); ` ` ` `return` `gcd(a, b - a); ` ` ` `} ` ` ` ` ` `// Function to compute the rounded value ` ` ` `public` `static` `long` `getRounding(` `long` `n, ` `long` `k) ` ` ` `{ ` ` ` `long` `rounding = (` `long` `)Math.Pow(10, k); ` ` ` ` ` `// Computing GCD ` ` ` `long` `result = gcd(rounding, n); ` ` ` ` ` `// Returning LCM (GCD * LCM = n * k) ` ` ` `return` `((rounding * n) / result); ` ` ` `} ` ` ` ` ` `// Driver Code ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` `long` `n = 375, k = 4; ` ` ` ` ` `// Function call ` ` ` `Console.Write( getRounding(n, k)); ` ` ` ` ` `} ` `} ` ` ` `// This code is contributed by Nitin Mittal. ` |

## PHP

`<?php ` `// PHP Code For Smallest number ` `// divisible by n and has ` `// at-least k trailing zeros ` `function` `gcd(` `$a` `, ` `$b` `) ` `{ ` ` ` ` ` `// Everything divides 0 ` ` ` `if` `(` `$a` `== 0 || ` `$b` `== 0) ` ` ` `return` `0; ` ` ` ` ` `// base case ` ` ` `if` `(` `$a` `== ` `$b` `) ` ` ` `return` `$a` `; ` ` ` ` ` `// a is greater ` ` ` `if` `(` `$a` `> ` `$b` `) ` ` ` `return` `gcd(` `$a` `- ` `$b` `, ` `$b` `); ` ` ` `return` `gcd(` `$a` `, ` `$b` `- ` `$a` `); ` `} ` ` ` `// Function to compute ` `// the rounded value ` `function` `getRounding(` `$n` `, ` `$k` `) ` `{ ` ` ` `$rounding` `= ` `intval` `(pow(10, ` `$k` `)); ` ` ` ` ` `// Computing GCD ` ` ` `$result` `= gcd(` `$rounding` `, ` `$n` `); ` ` ` ` ` `// Returning LCM (GCD * LCM = n * k) ` ` ` `return` `intval` `((` `$rounding` `* ` `$n` `) / ` ` ` `$result` `); ` `} ` ` ` `// Driver code ` `$n` `= 375; ` `$k` `= 4; ` ` ` `// Function call ` `echo` `getRounding(` `$n` `, ` `$k` `); ` ` ` `// This code is contributed by Sam007 ` `?> ` |

**Output :**

30000

This article is contributed by **Rohit Thapliyal**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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