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Program for Tower of Hanoi

  • Difficulty Level : Medium
  • Last Updated : 08 Jul, 2021

Tower of Hanoi is a mathematical puzzle where we have three rods and n disks. The objective of the puzzle is to move the entire stack to another rod, obeying the following simple rules: 

  1. Only one disk can be moved at a time.
  2. Each move consists of taking the upper disk from one of the stacks and placing it on top of another stack i.e. a disk can only be moved if it is the uppermost disk on a stack.
  3. No disk may be placed on top of a smaller disk.

Approach : 
 

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Take an example for 2 disks :
Let rod 1 = 'A', rod 2 = 'B', rod 3 = 'C'.

Step 1 : Shift first disk from 'A' to 'B'.
Step 2 : Shift second disk from 'A' to 'C'.
Step 3 : Shift first disk from 'B' to 'C'.

The pattern here is :
Shift 'n-1' disks from 'A' to 'B'.
Shift last disk from 'A' to 'C'.
Shift 'n-1' disks from 'B' to 'C'.

Image illustration for 3 disks :

faq.disk3



Examples: 
 

Input : 2
Output : Disk 1 moved from A to B
         Disk 2 moved from A to C
         Disk 1 moved from B to C

Input : 3
Output : Disk 1 moved from A to C
         Disk 2 moved from A to B
         Disk 1 moved from C to B
         Disk 3 moved from A to C
         Disk 1 moved from B to A
         Disk 2 moved from B to C
         Disk 1 moved from A to C

 

 

C++




// C++ recursive function to
// solve tower of hanoi puzzle
#include <bits/stdc++.h>
using namespace std;
 
void towerOfHanoi(int n, char from_rod,
                    char to_rod, char aux_rod)
{
    if (n == 1)
    {
        cout << "Move disk 1 from rod " << from_rod <<
                            " to rod " << to_rod<<endl;
        return;
    }
    towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
    cout << "Move disk " << n << " from rod " << from_rod <<
                                " to rod " << to_rod << endl;
    towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
}
 
// Driver code
int main()
{
    int n = 4; // Number of disks
    towerOfHanoi(n, 'A', 'C', 'B'); // A, B and C are names of rods
    return 0;
}
 
// This is code is contributed by rathbhupendra

Java




// JAVA recursive function to
// solve tower of hanoi puzzle
import java.util.*;
import java.io.*;
import java.math.*;
class GFG
{
static void towerOfHanoi(int n, char from_rod,
                    char to_rod, char aux_rod)
{
    if (n == 1)
    {
        System.out.println("Move disk 1 from rod "+
                           from_rod+" to rod "+to_rod);
        return;
    }
    towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
    System.out.println("Move disk "+ n + " from rod " +
                       from_rod +" to rod " + to_rod );
    towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
}
 
// Driver code
public static void  main(String args[])
{
    int n = 4; // Number of disks
    towerOfHanoi(n, 'A', 'C', 'B'); // A, B and C are names of rods
}
}
 
// This code is contributed by jyoti369

Python3




# Recursive Python function to solve tower of hanoi
 
def TowerOfHanoi(n , from_rod, to_rod, aux_rod):
    if n == 1:
        print("Move disk 1 from rod",from_rod,"to rod",to_rod)
        return
    TowerOfHanoi(n-1, from_rod, aux_rod, to_rod)
    print("Move disk",n,"from rod",from_rod,"to rod",to_rod)
    TowerOfHanoi(n-1, aux_rod, to_rod, from_rod)
         
# Driver code
n = 4
TowerOfHanoi(n, 'A', 'C', 'B')
# A, C, B are the name of rods
 
# Contributed By Harshit Agrawal

C#




// C# recursive program to solve tower of hanoi puzzle
using System;
class GFG
{
    static void towerOfHanoi(int n, char from_rod, char to_rod, char aux_rod)
    {
        if (n == 1)
        {
            Console.WriteLine("Move disk 1 from rod "
                              from_rod + " to rod " + to_rod);
            return;
        }
        towerOfHanoi(n-1, from_rod, aux_rod, to_rod);
        Console.WriteLine("Move disk " + n + " from rod "
                          from_rod + " to rod " + to_rod);
        towerOfHanoi(n-1, aux_rod, to_rod, from_rod);
    }
     
    //  Driver method
    public static void Main(String []args)
    {
        int n = 4; // Number of disks
        towerOfHanoi(n, 'A', 'C', 'B');  // A, B and C are names of rods
    }
}
 
//This code is contributed by shivanisinghss2110

PHP




<?php
 
// Tower of Hanoi (n-disk) algorithm in PHP with Display of Pole/rod
// Contents the 3 poles representation
$poles = array(array(), array(), array());
 
function TOH($n, $A="A", $B="B", $C="C"){
     
    if ($n > 0){
        TOH($n-1, $A, $C, $B);
        echo "Move disk from rod $A to rod $C \n";
        move($A, $C);
        dispPoles();
        TOH($n-1, $B, $A, $C);
    }
    else {
        return;
    }
}
 
function initPoles($n){
    global $poles;
 
    for ($i=$n; $i>=1; --$i){
        $poles[0][] = $i;
    }
}
 
 
function move($source, $destination){
    global $poles;
     
    // get source and destination pointers
    if ($source=="A") $ptr1=0;
    elseif ($source=="B") $ptr1 = 1;
    else $ptr1 = 2;
     
    if ($destination=="A") $ptr2 = 0;
    elseif ($destination=="B") $ptr2 = 1;
    else $ptr2 = 2;
     
    $top = array_pop($poles[$ptr1]);
    array_push($poles[$ptr2], $top);
}
 
function dispPoles(){ 
    global $poles;
    echo "A: [".implode(", ", $poles[0])."] ";
    echo "B: [".implode(", ", $poles[1])."] ";
    echo "C: [".implode(", ", $poles[2])."] ";
    echo "\n\n";
}
 
$numdisks = 4;
initPoles($numdisks);
echo "Tower of Hanoi Solution for $numdisks disks: \n\n";
dispPoles();
TOH($numdisks);
 
// This code is contributed by ShreyakChakraborty
?>

Javascript




<script>
// javascript recursive function to
// solve tower of hanoi puzzle
function towerOfHanoi(n, from_rod,  to_rod,  aux_rod)
{
        if (n == 1)
        {
            document.write("Move disk 1 from rod " + from_rod +
            " to rod " + to_rod+"<br/>");
            return;
        }
        towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
        document.write("Move disk " + n + " from rod " + from_rod +
        " to rod " + to_rod+"<br/>");
        towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
    }
 
    // Driver code
    var n = 4; // Number of disks
    towerOfHanoi(n, 'A', 'C', 'B'); // A, B and C are names of rods
 
// This code is contributed by gauravrajput1
</script>
Output
Move disk 1 from rod A to rod B
Move disk 2 from rod A to rod C
Move disk 1 from rod B to rod C
Move disk 3 from rod A to rod B
Move disk 1 from rod C to rod A
Move disk 2 from rod C to rod B
Move disk 1 from rod A to rod B
Move disk 4 from rod A to rod C
Move disk 1 from rod B to rod C
Move disk 2 from rod B to rod A
Move disk 1 from rod C to rod A
Move disk 3 from rod B to rod C
Move disk 1 from rod A to rod B
Move disk 2 from rod A to rod C
Move disk 1 from rod B to rod C
Output:

Tower of Hanoi Solution for 4 disks:

A: [4, 3, 2, 1] B: [] C: []

Move disk from rod A to rod B
A: [4, 3, 2] B: [1] C: []

Move disk from rod A to rod C
A: [4, 3] B: [1] C: [2]

Move disk from rod B to rod C
A: [4, 3] B: [] C: [2, 1]

Move disk from rod A to rod B
A: [4] B: [3] C: [2, 1]

Move disk from rod C to rod A
A: [4, 1] B: [3] C: [2]

Move disk from rod C to rod B
A: [4, 1] B: [3, 2] C: []

Move disk from rod A to rod B
A: [4] B: [3, 2, 1] C: []

Move disk from rod A to rod C
A: [] B: [3, 2, 1] C: [4]

Move disk from rod B to rod C
A: [] B: [3, 2] C: [4, 1]

Move disk from rod B to rod A
A: [2] B: [3] C: [4, 1]

Move disk from rod C to rod A
A: [2, 1] B: [3] C: [4]

Move disk from rod B to rod C
A: [2, 1] B: [] C: [4, 3]

Move disk from rod A to rod B
A: [2] B: [1] C: [4, 3]

Move disk from rod A to rod C
A: [] B: [1] C: [4, 3, 2]

Move disk from rod B to rod C
A: [] B: [] C: [4, 3, 2, 1]

Video Explanation

https://www.youtube.com/watch?v=YstLjLCGmgg

Related Articles 
 

 

References: 
http://en.wikipedia.org/wiki/Tower_of_Hanoi
This article is contributed by Rohit Thapliyal. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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