Problems associated with sorting and removal of duplicates is quite common in development domain and general coding as well. The sorting by frequency has been discussed, but sometimes, we even wish to remove the duplicates without using more LOC’s and in a shorter way. Let’s discuss certain ways in which this can be done.
Method #1 : Using count() + set() + sorted()
The sorted function can be used to sort the elements as desired, the frequency can be computed using the count function and removal of duplicates can be handled using the set function.
# Python3 code to demonstrate # sorting and removal of duplicates # Using sorted() + set() + count() # initializing list test_list = [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5] # printing original list print("The original list : " + str(test_list)) # using sorted() + set() + count() # sorting and removal of duplicates res = sorted(set(test_list), key = lambda ele: test_list.count(ele)) # print result print("The list after sorting and removal : " + str(res)) |
The original list : [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5] The list after sorting and removal : [2, 3, 6, 5]
Method #2 : Using Counter.most_common() + list comprehension
If one has a particular use case of sorting by the decreasing order of frequency, one can also use most-common function of Counter library to get frequency part.
# Python3 code to demonstrate # sorting and removal of duplicates # Using Counter.most_common() + list comprehension from collections import Counter # initializing list test_list = [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5] # printing original list print("The original list : " + str(test_list)) # using Counter.most_common() + list comprehension # sorting and removal of duplicates res = [key for key, value in Counter(test_list).most_common()] # print result print("The list after sorting and removal : " + str(res)) |
The original list : [5, 6, 2, 5, 3, 3, 6, 5, 5, 6, 5] The list after sorting and removal : [5, 6, 3, 2]
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