# Python | Remove duplicates based on Kth element tuple list

Sometimes, while working with records, we may have a problem in which we need to remove duplicates based on Kth element of tuple in list. This problem has application in domains which uses records as input. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using loop
This is a brute force method to perform this particular task. In this, we check for the Kth index of tuple and add to a set to keep record. If that value is already in the memory set, we discard it from result as it’s duplicate.

 `# Python3 code to demonstrate working of ` `# Remove duplicates based on Kth element tuple list ` `# Using loop ` ` `  `# initialize list  ` `test_list ``=` `[(``3``, ``1``, ``5``), (``1``, ``3``, ``6``), (``2``, ``1``, ``7``), ` `                        ``(``5``, ``2``, ``8``), (``6``, ``3``, ``0``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initialize K  ` `K ``=` `1`  ` `  `# Remove duplicates based on Kth element tuple list ` `# Using loop ` `temp ``=` `set``()    ` `res ``=` `[] ` `for` `ele ``in` `test_list: ` `    ``if` `ele[K] ``not` `in` `temp: ` `        ``res.append(ele) ` `        ``temp.add(ele[K]) ` ` `  `# printing result ` `print``(``"The list after removal of K based duplicates : "` `+` `str``(res)) `

Output :

The original list is : [(3, 1, 5), (1, 3, 6), (2, 1, 7), (5, 2, 8), (6, 3, 0)]
The list after removal of K based duplicates : [(3, 1, 5), (1, 3, 6), (5, 2, 8)]

Method #2 : Using `reduce() + lambda + keys()`

In this method, we perform the task of filtering using `reduce() + lambda`, and decide to append or not using the extracted keys using `keys()`. If key has already occurred, its discarded otherwise added.

 `# Python3 code to demonstrate working of ` `# Remove duplicates based on Kth element tuple list ` `# Using reduce() + lambda + keys() ` `from` `functools ``import` `reduce` ` `  `# initialize list  ` `test_list ``=` `[(``3``, ``1``), (``1``, ``3``), (``3``, ``2``), (``5``, ``2``), (``5``, ``3``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initialize K  ` `K ``=` `0` ` `  `# Remove duplicates based on Kth element tuple list ` `# Using reduce() + lambda + keys() ` `res ``=` `reduce``(``lambda` `sub, ele : ele[K] ``in` `dict``(sub).keys()  ` `                   ``and` `sub ``or` `sub ``+` `[ele], test_list, []) ` ` `  `# printing result ` `print``(``"The list after removal of K based duplicates : "` `+` `str``(res)) `

Output :

The original list is : [(3, 1), (1, 3), (3, 2), (5, 2), (5, 3)]
The list after removal of K based duplicates : [(3, 1), (1, 3), (5, 2)]

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