Python set symmetric_difference_update()

The symmetric difference of two sets is the set of elements which are in either of the sets but not in both of them.

symmetric-difference
Symmetric Difference is marked in Green

symmetric_difference() method returns a new set which contains symmetric difference of two sets. The symmetric_difference_update() method updates the set calling symmetric_difference_update() with the symmetric difference of sets.

Syntax:
A.symmetric_difference_update(B)
Parameters:
The symmetric_difference takes a single “set” as a argument.
Returns:
This method returns None (which indicates absence of a return value). It only updates the set calling symmetric_difference_update() with the symmetric difference of sets.

CODE 1

# Python code to demonstrate working of  
# symmetric_difference_update() 
  
A = {'p', 'a', 'w', 'a', 'n'} 
B = {'r', 'a', 'o', 'n', 'e'} 
  
# result is always none. 
result = A.symmetric_difference_update(B) 
  
print('A = ', A) 
print('B = ', B) 
print('result = ', result) 

Output:

('A = ', set(['e', 'o', 'p', 'r', 'w']))
('B = ', set(['a', 'r', 'e', 'o', 'n']))
('result = ', None)

CODE 2

# Python code to demonstrate working of  
# symmetric_difference_update() 
  
A = {'s', 'u', 'n', 'n', 'y'} 
B = {'b', 'u', 'n', 'n', 'y'} 
  
# result is always none. 
result = A.symmetric_difference_update(B) 
  
print('A = ', A) 
print('B = ', B) 
print('result = ', result) 

Output:

('A = ', set(['s', 'b']))
('B = ', set(['y', 'b', 'u', 'n']))
('result = ', None)

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