Python | Returning index of a sorted list
Sort a list in python and then return the index of elements in sorted order.
Examples:
Input : [2, 3, 1, 4, 5] Output : [2, 0, 1, 3, 4] After sorting list becomes [1, 2, 3, 4, 5] and their index as [2, 0, 1, 3, 4] Input : [6, 4, 7, 8, 1] Output : [4, 1, 0, 2, 3] After sorting the list becomes [1, 4, 6, 7, 8] and their index as [4, 1, 0, 2, 3].
Method 1
import numpys = numpy.array([2, 3, 1, 4, 5])sort_index = numpy.argsort(s)print(sort_index) |
Output :
[2, 0, 1, 3, 4]
Method 2
s = [2, 3, 1, 4, 5]li=[] for i in range(len(s)): li.append([s[i],i])li.sort()sort_index = [] for x in li: sort_index.append(x[1]) print(sort_index) |
Output:
[2, 0, 1, 3, 4]
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