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Python Program that prints the rows of a given length from a matrix

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  • Last Updated : 16 Nov, 2020

Given a Matrix, the following articles shows how to extract all the rows with a specified length.

Input : test_list = [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]], K = 3 
Output : [[1, 4, 6], [7, 3, 1]] 
Explanation : Extracted lists have length of 3.
Input : test_list = [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]], K = 4 
Output : [[3, 4, 5, 6]] 
Explanation : Extracted lists have length of 4. 

Method 1 : Using list comprehension and len()

In this, we perform the task of getting length using len() and list comprehension does the task of filtering all the rows which have a specified length.

Python3




# initializing list
test_list = [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 3
  
# list comprehension is used for extracting K len rows
res = [sub for sub in test_list if len(sub) == K]
  
# printing result
print("The filtered rows : " + str(res))

Output:

The original list is : [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]]

The filtered rows : [[1, 4, 6], [7, 3, 1]]

Method 2 : Using filter(), lambda and len()

In this, we perform the task of filtering using filter() and lambda. len() is used for finding length of rows.

Python3




# initializing list
test_list = [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 3
  
# filter() + lambda to filter out rows of len K
res = list(filter(lambda sub: len(sub) == K, test_list))
  
# printing result
print("The filtered rows : " + str(res))

Output:

The original list is : [[3, 4, 5, 6], [1, 4, 6], [2], [2, 3, 4, 5, 6], [7, 3, 1]]

The filtered rows : [[1, 4, 6], [7, 3, 1]]


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