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Python program to remove rows with duplicate element in Matrix
• Last Updated : 01 Oct, 2020

Given Matrix, remove all rows which have duplicate elements in them.

Input : test_list = [[4, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]]
Output : [[4, 3, 2]]
Explanation : [4, 3, 2] is the only unique row.

Input : test_list = [[4, 3, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]]
Output : []
Explanation : No unique row.

Method 1 : Using list comprehension + set() + len()

In this, we extract only the rows which remain in the same length after converting it into a set.

## Python3

 `# initializing list``test_list ``=` `[[``4``, ``3``, ``2``], [``7``, ``6``, ``7``], [``2``, ``4``, ``5``], [``8``, ``9``, ``9``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# set() removing all elements``# list comprehension used to filter``res ``=` `[sub ``for` `sub ``in` `test_list ``if` `len``(``set``(sub)) ``=``=` `len``(sub)]`` ` `# printing result``print``(``"Rows after removal : "` `+` `str``(res))`
Output
```The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
Rows after removal : [[4, 3, 2], [2, 4, 5]]

```

Method #2 : Using filter() + lambda + set() + len()

In this, we perform the task of filtering using filter() + lambda function, and set and len() are used to check.

## Python3

 `# initializing list``test_list ``=` `[[``4``, ``3``, ``2``], [``7``, ``6``, ``7``], [``2``, ``4``, ``5``], [``8``, ``9``, ``9``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# set() removing all elements``# filter() used to filter``res ``=` `list``(``filter``(``lambda` `ele: ``len``(``set``(ele)) ``=``=` `len``(ele), test_list))`` ` `# printing result``print``(``"Rows after removal : "` `+` `str``(res))`
Output
```The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
Rows after removal : [[4, 3, 2], [2, 4, 5]]

```

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