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Python program to remove rows with duplicate element in Matrix
  • Last Updated : 01 Oct, 2020

Given Matrix, remove all rows which have duplicate elements in them.

Input : test_list = [[4, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]] 
Output : [[4, 3, 2]] 
Explanation : [4, 3, 2] is the only unique row.

Input : test_list = [[4, 3, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]] 
Output : [] 
Explanation : No unique row. 
 

Method 1 : Using list comprehension + set() + len()

In this, we extract only the rows which remain in the same length after converting it into a set.



Python3




# initializing list
test_list = [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# set() removing all elements
# list comprehension used to filter
res = [sub for sub in test_list if len(set(sub)) == len(sub)]
  
# printing result
print("Rows after removal : " + str(res))
Output
The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
Rows after removal : [[4, 3, 2], [2, 4, 5]]

Method #2 : Using filter() + lambda + set() + len()

In this, we perform the task of filtering using filter() + lambda function, and set and len() are used to check.

Python3




# initializing list
test_list = [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# set() removing all elements
# filter() used to filter
res = list(filter(lambda ele: len(set(ele)) == len(ele), test_list))
  
# printing result
print("Rows after removal : " + str(res))
Output
The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]]
Rows after removal : [[4, 3, 2], [2, 4, 5]]

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