Sometimes, while working with python, we can have a problem in which we need to generate random number. This seems quite easy but sometimes we require a slight variation of it. That is, we require to generate random number from a list except K. Lets discuss certain ways in which this task can be performed.
Method #1 : Using choice()
+ list comprehension
The combination of above functions can be used to perform this task. In this, we first filter out the numbers except K using list comprehension and then feed that list to choice() for random number generation.
# Python3 code to demonstrate # Generate random number except K in list # using choice() + list comprehension import random # Initializing list test_list = [ 4 , 7 , 8 , 4 , 6 , 10 ] # printing original list print ( "The original list is : " + str (test_list)) # Initializing K K = 4 # Generate random number except K in list # using choice() + list comprehension res = random.choice([ele for ele in test_list if ele ! = K]) # printing result print ( "The random number except K is : " + str (res)) |
The original list is : [4, 7, 8, 4, 6, 10] The random number except K is : 8
Method #2 : Using filter() + lambda + choice()
This is yet another way in which this task can be performed. In this, we perform method of creating new list using filter and lambda.
# Python3 code to demonstrate # Generate random number except K in list # using choice() + filter() + lambda import random # Initializing list test_list = [ 4 , 7 , 8 , 4 , 6 , 10 ] # printing original list print ( "The original list is : " + str (test_list)) # Initializing K K = 4 # Generate random number except K in list # using choice() + filter() + lambda res = random.choice( list ( filter ( lambda ele: ele ! = K, test_list))) # printing result print ( "The random number except K is : " + str (res)) |
The original list is : [4, 7, 8, 4, 6, 10] The random number except K is : 8
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