Python | Generate random number except K in list
Sometimes, while working with python, we can have a problem in which we need to generate random number. This seems quite easy but sometimes we require a slight variation of it. That is, we require to generate random number from a list except K. Lets discuss certain ways in which this task can be performed.
Method #1 : Using choice() + list comprehension
The combination of above functions can be used to perform this task. In this, we first filter out the numbers except K using list comprehension and then feed that list to choice() for random number generation.
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# Python3 code to demonstrate # Generate random number except K in list# using choice() + list comprehensionimport random # Initializing list test_list = [4, 7, 8, 4, 6, 10] # printing original listprint("The original list is : " + str(test_list)) # Initializing K K = 4 # Generate random number except K in list# using choice() + list comprehensionres = random.choice([ele for ele in test_list if ele != K]) # printing result print ("The random number except K is : " + str(res)) |
The original list is : [4, 7, 8, 4, 6, 10] The random number except K is : 8
Method #2 : Using filter() + lambda + choice()
This is yet another way in which this task can be performed. In this, we perform method of creating new list using filter and lambda.
# Python3 code to demonstrate # Generate random number except K in list# using choice() + filter() + lambdaimport random # Initializing list test_list = [4, 7, 8, 4, 6, 10] # printing original listprint("The original list is : " + str(test_list)) # Initializing K K = 4 # Generate random number except K in list# using choice() + filter() + lambdares = random.choice(list(filter(lambda ele: ele != K, test_list))) # printing result print ("The random number except K is : " + str(res)) |
The original list is : [4, 7, 8, 4, 6, 10] The random number except K is : 8
