Related Articles

Related Articles

Python | Count the array elements with factors less than or equal to the factors of given x
  • Last Updated : 29 Jul, 2019

Given an array, the task is to count the elements of array whose factors are less than the given number x.

Examples:

Input: arr = [2, 12, 4, 6], x = 6
Output: 2
factors of x = 6 is [1, 2, 3]
factors of arr[0] = 2 is [1]
factors of arr[1] = 12 is [1, 2, 3, 4]
factors of arr[2] = 4 is [1, 2]
factors of arr[3] = 6 is [1, 2, 3]

so only arr[0] and arr[2] are the answer.

Approach:
Find out factors of all the elements and that of given xand after that compare all of them if factors of elements are less than that of factors of x, then increment the count.



Below is the implementation of above problem –

filter_none

edit
close

play_arrow

link
brightness_4
code

from math import ceil, sqrt
   
# function to count the factors of an array
def factorscount(x):
    count = 0
    for i in range(1,ceil(sqrt(x))):
        if x%i==i:
            count+=1
        else:
            count+=2
    return count
   
def Totalcount(arr, x):
      
    # count of factors of  given x
    count_fac = factorscount(x)
      
    # store the count of each factors
    arr_fac = [factorscount(i) for i in arr]
   
    ans = 0
   
    for i in arr_fac:
        # if factors count of element of array is
        #small than that of given number
        if i<count_fac:
            ans+=1
   
    return ans
   
   
# Driver code
   
arr = [2,12,4,6]
x = 6
print(Totalcount(arr, x))

chevron_right


Output:

2

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.




My Personal Notes arrow_drop_up
Recommended Articles
Page :