Input: N = 3, M = 7
The least numbers greater than equals to 3 and 7 which is a multiple of 3 and 7 is 21.
Input: N = 5, M = 5
The least numbers greater than equals to 5 and 5 which is a multiple of 5 and 5 is 5.
Approach: As we know that product of two numbers equals to the product of their Greatest Common Divisor(GCD) and Least Common Multiple(LCM). So, the LCM of the two given prime numbers can be given by: .
Since the GCD two different prime numbers are 1, Therefore , and if the two given numbers are same then the LCM is the number itself.
Below is the implementation of the above approach:
Time Complexity: O(1)
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