Program to differentiate the given Polynomial

Given polynomial string str, the task is to differentiate the given string and print the string after differentiating it. 
Note: The input format is such that there is a white space between a term and the ‘+’, ’-’ symbol
Examples:

Input: str = “4X³ + 3X¹ + 2X²” 
Output: “12X² + 3X⁰ + 4X¹” 
Explanation:
The derivative of p(x) = A*X^N is p'(x) = A * N * X^{N – 1}
Input: str = “5X⁴ + 6X² + 5X²” 
Output: “20X³ + 12X¹ + 10X¹”  

Approach: The idea is to observe that when the given equation consists of multiple polynomials 

, the differentiation of the given polynomial 

. And, it is known that the derivative of 

is 

Therefore, we split the given string and differentiate every term in it. 
Below is the implementation of the above approach:

C++

// C++ program to differentiate the
// given polynomial

#include "bits/stdc++.h"
#define MOD (1e9 + 7);
using ll = int64_t;
using ull = uint64_t;
#define ll long long
using namespace std;

// Function to differentiate the
// given term
string diffTerm(string pTerm)
{
    // Get the coefficient
    string coeffStr = "", S = "";
    int i;

    // Loop to get the coefficient
    for (i = 0; pTerm[i] != 'x'; i++)
        coeffStr.push_back(pTerm[i]);

    long long coeff
        = atol(coeffStr.c_str());

    // Loop to get the power of each term
    string powStr = "";
    for (i = i + 2; i != pTerm.size(); i++)
        powStr.push_back(pTerm[i]);

    long long power
        = atol(powStr.c_str());
    string a, b;

    // Converting the value
    // to the string
    ostringstream str1, str2;

    // For ax^n, we find (n)*a*x^(n-1)
    coeff = coeff * power;
    str1 << coeff;
    a = str1.str();
    power--;
    str2 << power;
    b = str2.str();
    S += a + "X^" + b;

    return S;
}

// Function to differentiate the
// given polynomial
string diffstr(string& poly)
{

    // We use istringstream to get
    // the input in tokens
    istringstream is(poly);

    string pTerm, S = "";

    // For every token, compute the
    // differentiation
    while (is >> pTerm) {

        // If the token is equal to
        // '+', '-' then
        // continue with the string
        if (pTerm == "+") {
            S += " + ";
            continue;
        }

        if (pTerm == "-") {
            S += " - ";
            continue;
        }

        // Otherwise find the differentiation
        // of that particular term
        else
            S += diffTerm(pTerm);
    }
    return S;
}

// Driver code
int main()
{
    string str = "5x^4 + 6x^2 + 5x^2";
    cout << diffstr(str);
    return 0;
}

Python3

# Python3 program to differentiate
# the given polynomial
MOD = (1e9 + 7)

# Function to differentiate
# the given term
def diffTerm(pTerm):

    # Get the coefficient
    coeffStr = ""
    S = ""

    # Loop to get the
    # coefficient
    i = 0
    while (i < len(pTerm) and
           pTerm[i] != 'x'):
        coeffStr += (pTerm[i])
        i += 1

    coeff = int(coeffStr)

    # Loop to get the power
    # of each term
    powStr = ""
    j = i + 2
    while j < len(pTerm):
        powStr += (pTerm[j])
        j += 1

    power = int(powStr)

    # For ax^n, we find
    # (n)*a*x^(n-1)
    coeff = coeff * power
    a = str(coeff)
    power -= 1
    b = str(power)
    S += a + "X^" + b

    return S

# Function to differentiate
# the given polynomial
def diffstr(poly):

    pTerm = poly.split(" ")
    S = ""

    for i in range(len(pTerm)):

        # If the token is equal to
        # '+', '-' then
        # continue with the string
        if (pTerm[i] == "+"):
            S += " + "
            continue

        if (pTerm[i] == "-"):
            S += " - "
            continue

        # Otherwise find the differentiation
        # of that particular term
        else:
            S += diffTerm(pTerm[i])

    return S

# Driver code
if __name__ == "__main__":

    st = "5x^4 + 6x^2 + 5x^2"
    print(diffstr(st))

# This code is contributed by Chitranayal

Output:

20X^3 + 12X^1 + 10X^1