# Program to check whether the given number is Buzz Number or not

• Last Updated : 31 Jan, 2022

A number is said to be Buzz Number if it ends with 7 OR is divisible by 7.
The task is to check whether the given number is buzz number or not.
Examples:

```Input : 63
Output : Buzz Number
Explanation: 63 is divisible by 7, one
of the condition is satisfied.

Input : 72
Output : Not a Buzz Number
Explanation: 72 % 7 != 0, 72 is neither
divisible by 7 nor it ends with 7 so
it is not a Buzz Number.```

## C++

 `// C++ program to check whether the``// given number is Buzz Number or not.``#include ``#include ``using` `namespace` `std;` `// function to check BUzz number.``bool` `isBuzz(``int` `num)``{``    ``// checking if the number``    ``// ends with 7 and is divisible by 7``    ``return` `(num % 10 == 7 || num % 7 == 0);``}` `// Driver method``int` `main(``void``)``{``    ``int` `i = 67, j = 19;``    ``if` `(isBuzz(i))``        ``cout << ``"Buzz Number\n"``;``    ``else``        ``cout << ``"Not a Buzz Number\n"``;``    ``if` `(isBuzz(j))``        ``cout << ``"Buzz Number\n"``;``    ``else``        ``cout << ``"Not a Buzz Number\n"``;``}`

## Java

 `// Java program to check whether the``// given number is Buzz number or not``import` `java.io.*;``import` `java.util.*;``class` `GFG {` `    ``// function to check BUzz number.``    ``static` `boolean` `isBuzz(``int` `num)``    ``{``        ``// checking if the number``        ``// ends with 7 and is divisible by 7``        ``return` `(num % ``10` `== ``7` `|| num % ``7` `== ``0``);``    ``}` `    ``// Driver method``    ``public` `static` `void` `main(String args[])``    ``{``        ``int` `i = ``67``, j = ``19``;``        ``if` `(isBuzz(i))``            ``System.out.println(``"Buzz Number"``);``        ``else``            ``System.out.println(``"Not a Buzz Number"``);``        ``if` `(isBuzz(j))``            ``System.out.println(``"Buzz Number"``);``        ``else``            ``System.out.println(``"Not a Buzz Number"``);``    ``}``}``// This code is contributed by Nikita Tiwari.`

## Python3

 `# Python program to check whether the``# given number is Buzz Number or not.` `# function to check BUzz number.``def` `isBuzz(num) :``    ` `    ``# checking if the number``    ``# ends with 7 and is divisible by 7``    ``return` `(num ``%` `10` `=``=` `7` `or` `num ``%` `7` `=``=` `0``)` `# Driver method``i ``=` `67``j ``=` `19``if` `(isBuzz(i)) :``    ``print` `(``"Buzz Number"``)``else` `:``    ``print` `(``"Not a Buzz Number"``)``if` `(isBuzz(j)) :``    ``print` `(``"Buzz Number"``)``else` `:``    ``print` `(``"Not a Buzz Number"``)   `

## PHP

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## C#

 `// C# program to check whether the``// given number is Buzz number or not``using` `System;` `class` `GFG {` `    ``// function to check BUzz number.``    ``static` `bool` `isBuzz(``int` `num)``    ``{``        ` `        ``// checking if the number``        ``// ends with 7 and is``        ``// divisible by 7``        ``return` `(num % 10 == 7 || num % 7 == 0);``    ``}` `    ``// Driver method``    ``public` `static` `void` `Main()``    ``{``        ``int` `i = 67, j = 19;``        ` `        ``if` `(isBuzz(i))``            ``Console.WriteLine(``"Buzz Number"``);``        ``else``            ``Console.Write(``"Not a Buzz Number"``);``            ` `        ``if` `(isBuzz(j))``            ``Console.Write(``"Buzz Number"``);``        ``else``            ``Console.Write(``"Not a Buzz Number"``);``    ``}``}` `// This code is contributed by Nitin mittal.`

## Javascript

 ``

Output:

```Buzz Number
Not a Buzz Number```

Time complexity : O(1) as there are atomic statements and no loops.

Auxiliary Space: O(1)
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