Skip to content
Related Articles

Related Articles

Improve Article

Print the given 3 string after modifying and concatenating

  • Last Updated : 18 May, 2021

Given three strings(without spaces). The task is to print the new string after modifying the three given string as follows: 
 

  • Replace all the vowels present in the first string with “*”.
  • Don’t change anything in the second string.
  • Replace all the consonants in the third string with “$”.
  • Concatenate all of the three string to obtain the new string.

Examples: 
 

Input : how are you
Output : h*ware$ou

Input : geeks for geeks
Output : g**ksfor$ee$$

 

The idea is to traverse the first string and keep checking if any character is vowel or not. Replace the character in the first string which is vowel with “*”. Similarly, traverse the third string and keep checking if any character is not a vowel. If a character in the third string is not a vowel(then it is a consonant), replace it with ‘$’.
Finally, concatenate the three strings and print the newly concatenated string. 
 

C++




// CPP program to modify the given strings
#include <iostream>
#include <string.h>
using namespace std;
 
// Function to modify the given three strings
string modifyStr(string str1, string str2, string str3)
{
    // Modifying first string
    for (int i = 0; i < str1.length(); i++) {
        if (str1[i] == 'a' || str1[i] == 'e' ||
            str1[i] == 'i' || str1[i] == 'o' ||
            str1[i] == 'u')
            str1[i] = '*';
    }
 
    // Modifying third string
    for (int i = 0; i < str3.length(); i++) {
        if (str3[i] != 'a' && str3[i] != 'e' &&
            str3[i] != 'i' && str3[i] != 'o' &&
            str3[i] != 'u')
            str3[i] = '$';
    }
 
    // Concatenating the three strings
    return (str1 + str2 + str3);
}
 
// Driver code
int main()
{
    string str1 = "how";
    string str2 = "are";
    string str3 = "you";
 
    cout << modifyStr(str1, str2, str3);
 
    return 0;
}

Java




// JAVA program to modify the given Strings
class GFG
{
 
// Function to modify the given three Strings
static String modifyStr(String str1, String str2, String str3)
{
    // Modifying first String
    for (int i = 0; i < str1.length(); i++) {
        if (str1.charAt(i) == 'a' || str1.charAt(i) == 'e' ||
            str1.charAt(i) == 'i' || str1.charAt(i) == 'o' ||
            str1.charAt(i) == 'u')
            str1 = str1.substring(0, i)+ '*' +
                   str1.substring(i + 1);
    }
 
    // Modifying third String
    for (int i = 0; i < str3.length(); i++) {
        if (str3.charAt(i) != 'a' && str3.charAt(i) != 'e' &&
            str3.charAt(i) != 'i' && str3.charAt(i) != 'o' &&
            str3.charAt(i) != 'u')
            str3 = str3.substring(0, i)+ '$' +
                   str3.substring(i + 1);
    }
 
    // Concatenating the three Strings
    return (str1 + str2 + str3);
}
 
// Driver code
public static void main(String[] args)
{
    String str1 = "how";
    String str2 = "are";
    String str3 = "you";
 
    System.out.print(modifyStr(str1, str2, str3));
}
}
 
// This code is contributed by 29AjayKumar

Python3




# Python3 program to modify the given Strings
 
# Function to modify the given three Strings
def modifyStr(str1, str2, str3):
     
    # Modifying first String
    for i in range(len(str1)):
        if (str1[i] == 'a' or str1[i] == 'e' or
            str1[i] == 'i' or str1[i] == 'o'
            or str1[i] == 'u'):
            str1 = str1[0:i] + '*' + str1[i + 1:];
     
 
    # Modifying third String
    for i in range(len(str3)):
        if (str3[i] != 'a' and str3[i] != 'e' and
            str3[i] != 'i' and str3[i] != 'o'
            and str3[i] != 'u'):
            str3 = str3[0: i] + '$' + str3[i + 1:];
     
    # Concatenating the three Strings
    return (str1 + str2 + str3);
 
# Driver code
if __name__ == '__main__':
    str1 = "how";
    str2 = "are";
    str3 = "you";
 
    print(modifyStr(str1, str2, str3));
     
# This code is contributed by 29AjayKumar

C#




// C# program to modify the given Strings
using System;
 
class GFG
{
 
// Function to modify the given three Strings
static String modifyStr(String str1, String str2, String str3)
{
    // Modifying first String
    for (int i = 0; i < str1.Length; i++)
    {
        if (str1[i] == 'a' || str1[i] == 'e' ||
            str1[i] == 'i' || str1[i] == 'o' ||
            str1[i] == 'u')
            str1 = str1.Substring(0, i)+ '*' +
                str1.Substring(i + 1);
    }
 
    // Modifying third String
    for (int i = 0; i < str3.Length; i++)
    {
        if (str3[i] != 'a' && str3[i] != 'e' &&
            str3[i] != 'i' && str3[i] != 'o' &&
            str3[i] != 'u')
            str3 = str3.Substring(0, i)+ '$' +
                str3.Substring(i + 1);
    }
 
    // Concatenating the three Strings
    return (str1 + str2 + str3);
}
 
// Driver code
public static void Main(String[] args)
{
    String str1 = "how";
    String str2 = "are";
    String str3 = "you";
 
    Console.Write(modifyStr(str1, str2, str3));
}
}
 
// This code is contributed by PrinciRaj1992

Javascript




<script>
 
// Javascript program to modify the given Strings
 
// Function to modify the given three Strings
function modifyStr(str1, str2, str3)
{
    // Modifying first String
    for(var i = 0; i < str1.length; i++)
    {
        if (str1.charAt(i) == 'a' ||
            str1.charAt(i) == 'e' ||
            str1.charAt(i) == 'i' ||
            str1.charAt(i) == 'o' ||
            str1.charAt(i) == 'u')
            str1 = str1.substring(0, i) + '*' +
                   str1.substring(i + 1);
    }
 
    // Modifying third String
    for(var i = 0; i < str3.length; i++)
    {
        if (str3.charAt(i) != 'a' &&
            str3.charAt(i) != 'e' &&
            str3.charAt(i) != 'i' &&
            str3.charAt(i) != 'o' &&
            str3.charAt(i) != 'u')
            str3 = str3.substring(0, i) + '$' +
                   str3.substring(i + 1);
    }
 
    // Concatenating the three Strings
    return (str1 + str2 + str3);
}
 
// Driver code
var str1 = "how";
var str2 = "are";
var str3 = "you";
 
document.write(modifyStr(str1, str2, str3));
 
// This code is contributed by Ankita saini
 
</script>
Output: 
h*ware$ou

 

Want to learn from the best curated videos and practice problems, check out the C++ Foundation Course for Basic to Advanced C++ and C++ STL Course for the language and STL. To complete your preparation from learning a language to DS Algo and many more, please refer Complete Interview Preparation Course.



My Personal Notes arrow_drop_up
Recommended Articles
Page :